What’s the answer to the problem
1 answer:
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Answer:
see explanation
Step-by-step explanation:
Using the sum/ difference → product formula
cos x - cos y = - 2sin( )sin (
)
sin x - sin y = 2cos ( )sin (
)
Given
(cosA - cosB)² + (sinA - sinB )²
= [ - 2sin()sin(
) ]² + [ 2cos(
)sin(
) ]²
= 4sin² ( )sin² (
) + 4cos² (
)sin² (
)
= 4sin² ( )[ sin² (
) + cos² (
) ← sin²x + cos²x = 1
= 4sin² ( ) × 1
= 4sin² ( ) = right side ⇒ proven
Answer: Hello!
A second order differential equation has the next shape:
where p(t), q(t) and g(t) are functions of t, that can be constant numbers for example.
And is called homogeneus when g(t) = 0, so you have:
Then a second order differential equation is homogeneus ef every term involve either y or the derivatives of y.