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ollegr [7]
3 years ago
6

Helppp mee nowww I will give ya points and brianly est

Mathematics
1 answer:
asambeis [7]3 years ago
8 0
X would be -5

Hope this helps :)
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the length of a rectangle is 7 yd more than 5 times the width. the perimeter is 150 yd. find the length and the width.
Vaselesa [24]
P = 2(L + W)
P = 150
L = 5W + 7

150 = 2(5W + 7 + W)
150 = 2(6W + 7)
150 = 12W + 14
150 - 14 = 12W
136 = 12W
136/12 = W
11.33 (or 11 1/3) = W <=== width

L = 5W + 7
L = 5(34/3) + 7
L = 170/3 + 7
L = 170/3 + 21/3
L = 191/3 (or 63 2/3) = L <=== length
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What is the surface ara of a sphere with a diameter of 16cm
avanturin [10]

Answer:

1024pi cm²

Step-by-step explanation:

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3 years ago
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Write a variable expression to describe the rule for the sequence. Then find the 100th term in the sequence. –4, 1, 6, 11, 16, .
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a+(n-1)d

Step-by-step explanation:

491

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3 years ago
The slope of the line whose equation is given
Mrac [35]
The slope is 9                
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4 years ago
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Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
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