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charle [14.2K]
3 years ago
6

Why does humus tend to increase with the clay content of soil? A. As the clay content increases, the amount of plant lignin in t

he soil increases. B. As the clay content increases, there is more surface area in the soil for organic matter to adsorb to, which increases the rate of decomposition. C. As the clay content increases, the permeability decreases, which increases the rate of decomposition. D. As the clay content increases, there is more surface area in the soil for organic matter to adsorb to, which decreases the rate of decomposition.
Physics
2 answers:
Kipish [7]3 years ago
7 0
<span>As the clay content increases, there is more surface area in the soil for organic matter to adsorb to, which decreases the rate of decomposition.</span>
Vanyuwa [196]3 years ago
4 0

Answer: B. As the clay content increases, there is more surface area in the soil for organic matter to adsorb to, which increases the rate of decomposition.

Explanation:

Clay is a finely grained material obtained from the weathering of the natural rock. It is mixed with the valuable materials such as metal oxides, organic matter, quartz which are mostly composed of phyllosilicate minerals that contains a variable amount of water trapped minerals. The clay in any type of soil increases the surface area for the absorption of water and organic matter. The increase in the organic matter in the soil will increase the abundance of soil microbes which increases the rate of decomposition of the dead and decaying matter like shed leaves, dried grasses and animal dung. This helps in formation of humus in the soil and keeps the soil fertile.

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A ball rolls across a floor with an acceleration of 0.100 m/s2 in a direction opposite to its velocity. The ball has a velocity
Westkost [7]

Answer:

4.15 m/s

Explanation:

Its given that acceleration is 0.1 m/s² with a direction opposite to the velocity. Since, the direction of acceleration is opposite to the velocity, this gives us a hint that the velocity is decreasing and so acceleration would be negative.

i.e.

acceleration = a = - 0.1 m/s²

Distance covered = S = 6m

Velocity after covering 6 meters = Final velocity = v_{f} = 4 m/s

We need to find the initial speed, which will be the same as the magnitude of initial velocity.

Initial velocity = v_{i} =  ?

3rd equation of motion relates the acceleration, distance, final velocity and initial velocity as:

2aS = (v_{f})^{2}-(v_{i})^{2}

Using the known values in the formula, we get:

2(-0.1)(6)=(4)^{2}- (v_{i})^{2}\\\\ (v_{i})^{2}=16+1.2\\\\ (v_{i})^{2}=17.2\\\\ v_{i}=4.15

Thus, the initial speed of the ball was 4.15 m/s

3 0
4 years ago
Is there a serve zone?
Lera25 [3.4K]

Answer:

When it comes to serving, the court is divided into six zones. Right back is zone one, right front is zone two, middle front is zone three, left front is zone four, left back is zone five and middle back is zone six.

Explanation:

7 0
3 years ago
Read 2 more answers
A cruise ship travels directly toward the dock at a speed of 12 m/s
Hatshy [7]

Thanks for sharing that information.  After extensive calculation,
we can say with assurance that after some number of seconds,
a loud "crunch" is perceived by the souls aboard the ill-fated vessel.

3 0
4 years ago
PlzHELP
Naddika [18.5K]
 Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.Displacement<span> is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.

</span>To calculate displacement<span>, simply draw a vector from your starting point to your final position and solve for the length of this line. If your starting and ending position are the same, like your circular 5K route, then your </span>displacement<span> is 0. In physics, </span>displacement<span> is represented by Δs.
 
 For me to solve this I would need to know the time, but I can give you a handy displacement calculator I used that helped me. 
 
https://www.easycalculation.com/physics/classical-physics/constant-acc-displacement.php

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8 0
3 years ago
One end of a metal rod is in contact with a thermal reservoir at 745. K, and the other end is in contact with a thermal reservoi
Masteriza [31]

Answer:

a)S_1=-9.65}\ J/K

b)S_2=71.18\ J/K

c) 0 J/K

d)S= 61.53 J/K

Explanation:

Given that

T₁ = 745 K

T₂ = 101 K

Q= 7190 J

a)

The entropy change of reservoir 745 K

S_1=-\dfrac{7190}{745}\ J/K

Negative sign because heat is leaving.

S_1=-9.65}\ J/K

b)

The entropy change of reservoir 101 K

S_2=\dfrac{7190}{101}\ J/K

S_2=71.18\ J/K

c)

The entropy change of the rod will be zero.

d)

The entropy change of the system

S= S₁ + S₂

S = 71.18 - 9.65 J/K

S= 61.53 J/K

3 0
4 years ago
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