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2 years ago

12

In an atom, electrons ____.

2 answers:

sergejj [24]2 years ago

8 0

A) travel outside the necleus

Lesechka [4]2 years ago

7 0

The correct answer for this would be travel outside the nucleus

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If two rocks with masses of 1 and 10 kilograms. What is the relation between their inertias Between their masses Between their w

Arada [10]

Greater the mass greater is inertia. Greater the inertia greater is the force required to stop motion of an object. Linear motion depends only on mass whereas rotational motion depends on mass, size and shape of an object. So conclusion is that it would be difficult to stop 10 kg mass cuz of greater inertia compared to 1kg mass. Hope it clears your doubt.

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3 years ago

assuming that the air temperature is constant, what happens to a hot air balloon if it goes too far up in the atmosphere , where

PIT_PIT [208]

Hello!

The balloon explodes, because the pressure builds up inside and the air want to expand. Letter a)

Hugs!

7 0

3 years ago

7. How is the current found in a parallel circuit?

Naya [18.7K]

Answer:

the current in a parallel circuit is found by idk

Explanation:

4 0

3 years ago

A car battery with a 12 V emf and an internal resistance of 0.11 Ω is being charged with a current of 56 A. What are (a) the pot

denpristay [2]

Answer:

Part a)

V = 18.16 V

Part b)

$P_r = 345 Watt$

Part c)

P = 672 Watt

Part d)

V = 5.84 V

Part e)

$P_r = 345 Watt$

Explanation:

Part a)

When battery is in charging mode

then the potential difference at the terminal of the cell is more than its EMF and it is given as

$\Delta V = E + i r$

here we have

$E = 12 V$

$i = 56 A$

$r = 0.11$

now we have

$\Delta V = 12 + (0.11)(56) = 18.16 V$

Part b)

Rate of energy dissipation inside the battery is the energy across internal resistance

so it is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

Part c)

Rate of energy conversion into EMF is given as

$P_{emf} = i E$

$P_{emf} = (56)(12)$

$P_{emf} = 672 Watt$

Now battery is giving current to other circuit so now it is discharging

now we have

Part d)

$V = E - i r$

$V = 12 - (56)(0.11)$

$V = 12 - 6.16 = 5.84 V$

Part e)

now the rate of energy dissipation is given as

$P_r = i^2 r$

$P_r = 56^2 (0.11)$

$P_r = 345 W$

7 0

3 years ago

For safety reasons, a worker’s eye travel time in a certain operation must be separated from the manual elements that follow. Th

iogann1982 [59]

Answer:

The answer is 12.67 TMU

Explanation:

Recall that,

worker’s eyes travel distance must be = 20 in.

The perpendicular distance from her eyes to the line of travel is =24 in

What is the MTM-1 normal time in TMUs that should be allowed for the eye travel element = ?

Now,

We solve for the given problem.

Eye travel is = 15.2 * T/D

=15.2 * 20 in/24 in

so,

= 12.67 TMU

Therefore, the MTM -1 of normal time that should be allowed for the eye travel element is = 12.67 TMU

7 0

3 years ago