3 years ago

In an atom, electrons ____.

Physics

2 answers:

sergejj [24]3 years ago

8 0

A) travel outside the necleus

Lesechka [4]3 years ago

7 0

The correct answer for this would be travel outside the nucleus

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A 7.7 kg sphere makes a perfectly inelastic collision with a second sphere initially at rest. The composite system moves with a

klemol [59]

Answer:

15.4 kg.

Explanation:

From the law of conservation of momentum,

Total momentum before collision = Total momentum after collision

mu+m'u' = V(m+m').................... Equation 1

Where m = mass of the first sphere, m' = mass of the second sphere, u = initial velocity of the first sphere, u' = initial velocity of the second sphere, V = common velocity of both sphere.

Given: m = 7.7 kg, u' = 0 m/s (at rest)

Let: u = x m/s, and V = 1/3x m/s

Substitute into equation 1

7.7(x)+m'(0) = 1/3x(7.7+m')

7.7x = 1/3x(7.7+m')

7.7 = 1/3(7.7+m')

23.1 = 7.7+m'

m' = 23.1-7.7

m' = 15.4 kg.

Hence the mass of the second sphere = 15.4 kg

7 0

3 years ago

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What mass of a material with density Ï is required to make a hollow spherical shell having inner radius r1 and outer radius r2?

inysia [295]

Yes, there are! r1 and r2 are numbers. The volume of the hollow shell is 4 π 3 ( r 3 1 − r 3 2 ) 4π3(r13−r23). Now multiply by ρ to get the mass.

3 0

3 years ago

Convert 2536 mm/min to m/s. Use dimensional analysis.

Deffense [45]

Answer:

As we know that, 

1 mm/min = 1.66667E-5 m/s
1 m/s = 60000 mm/min

Now, come to the question - 

$\\ \implies \sf \: 2536 \times 1.66667E-5 m/s \\ \\ \\ \implies \sf \blue{0.0422666667 \:m/s } \\$

Result : 2536 mm/min = 0.0422666667 m/s.

6 0

4 years ago

The density for gold is 19.3 g/cm3. What would be the mass of a 45 cm3 piece of gold?

lyudmila [28]

Answer:

868.5 g

Explanation:

Mass= Density x Volume

Mass= 19.3 x 45

=868.5

6 0

3 years ago

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Does a horseshoe go on the hoof or around it

Illusion [34]

Um I believe that it goes on top of the hoof

4 0

4 years ago