The bigger one as the luminosity has a direct exponential relationship with R of the star so the star which has more surface area will be more luminous than the smaller one
Answer:
I am sure the awnser to this is
B. vibrate
You can find the emf of the battery by using:
Q = CV.
Q = Charge in capacitor plates = 30μC
C = Capacitance of the capacitor = 30μF
V = Q/C = 30/30 = 1V
Ans: The emf of the battery = 1V.
Answer:
The work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.
Explanation:
Given;
potential difference between the plates, V = 10 V
length of each square side of the plates, L = 20 cm = 0.2 m
area of the plates, A = 0.2 x 0.2 = 0.04 m²
separation of the plates, d = 3 cm = 0.03 m
The work done in bringing the plates together is calculated as;
W = ¹/₂qV

Therefore, the work done in bringing the plates together is 5.9 x 10⁻¹⁰ J.