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3 years ago

If development does not occur in stages, then it is likely that development can be described as __________.

Physics

1 answer:

inna [77]3 years ago

5 0

Answer:

I think it's D

ffjfjfjfjrjfjfjfjfj

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Can you do it for me pls thank and if you do I mark you brainlies

Art [367]

Answer:

800pa

Explanation:

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6 0

3 years ago

Two hockey pucks are sliding along the ice, towards the same goal, one directly in front of the other. The hockey puck in front

grandymaker [24]

Answer: A.9.2m/s

Explanation:

6 0

3 years ago

A bullet with kinetic energy of 400J strikes a wooden block where a 8.00x10N resistive force stops the bullet what is the penetr

tia_tia [17]

The "penetration of the bullet" is 5 m

<u>Explanation</u>:

A "bullet" with "kinetic energy" of = 400J

A resistive force stops the bullet = 8.00 x 10 N

Work = change in energy

Work = ∆ Kinetic Energy (equation 1)

Work = $F\times d$ (equation 2)

From equations 1 and 2 we have,

$F\times d$ = ∆ Kinetic Energy

Where ,

Kinetic Energy = 400 J

F = 8.00 x 10 N

(8.00 x 10 N) d = 400 J

(80 N) d = 400 J

$d=\frac{400}{80}$

d = 5 m

The penetration of the bullet is 5 m

5 0

3 years ago

A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a

bixtya [17]

Answer:

$B_e = 2.72 \times 10^{-4} T$

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

$F = qvB$

$\frac{mv^2}{r} = qvB$

now we have

$r = \frac{mv}{qB}$

since here radius of proton and electron will be same

so we will have

$r_e = r_p$

$\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}$

so we have

$B_e = \frac{B_p m_e}{m_p}$

given that

$B_p = 0.50 T$

$m_e = 9.11 \times 10^{-31} kg$

$m_p = 1.67 \times 10^{-27} kg$

so we have

$B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}$

$B_e = 2.72 \times 10^{-4} T$

4 0

3 years ago

Read 2 more answers

You wish to buy a motor that will be used to lift a30-kg bundle of shingles from the ground to the roof of a house. The shingles

hodyreva [135]

Answer:

the minimum value of torque is 101.7 N-m.

Explanation:

Given that,

Mass of bundle of shingles, m = 30 kg

Upward acceleration of the shingles,

The radius of the motor of the pulley, r = 0.3 m

Let T is the tension acting on the shingles when it is lifted up. It can be calculated as :

T-mg=ma

T=m(g+a)

$T=10\times (9.8+1.5)\\T = 113 N$

Let $\tau$ is the minimum torque that the motor must be able to provide. It is given by :

$\tau=r\times T\tau=0.3\times 339\tau=101.7\ N-m$

the minimum value of torque is $101.7 N-m.$

6 0

3 years ago