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ArbitrLikvidat [17]
4 years ago
15

A sperm whale can accelerate at about 0.0900 m/s 2 when swimming on the surface of the ocean. How far will a sperm whale travel

if it starts at a speed of 0.700 m/s and accelerates to a speed of 2.18 m/s ? Assume the whale travels in a straight line.
Physics
1 answer:
Mars2501 [29]4 years ago
5 0

Answer:

s = 23.68 m

Explanation:

given,

acceleration of the sperm whale = 0.09 m/s²

initial speed of the whale, u = 0.7 m/s

final speed of the whale, v = 2.18 m/s

Distance traveled by the sperm whale = ?

Using equation of motion

 v² = u² + 2 a s

 2.18² = 0.7² + 2 x 0.09 x s

 0.18 s = 4.2624

 s = 23.68 m

Distance traveled by the whale is equal to s = 23.68 m

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skad [1K]

Answer:

g' = 13.5 m/s²

Explanation:

The acceleration due to gravity on surface of earth is given by the formula:

g = GMe/Re²   --------------- euation 1

where,

g = acceleration due to gravity on surface of earth

G = Universal Gravitational Constant

Me = Mass of Earth

Re = Radius of Earth

Now, the the acceleration due to gravity on the surface of Kepler-62e is:

g' = GM'/R'²   --------------- euation 1

where,

g' = acceleration due to gravity on surface of Kepler-62e

G = Universal Gravitational Constant

M' = Mass of Kepler-62e = 3.57 Me

R' = Radius of Kepler-62e = 1.61 Re

Therefore,

g' = G(3.57 Me)/(1.61 Re)²

g' = 1.38 GMe/Re²

using equation 1:

g' = 1.38 g

where,

g = 9.8 m/s²

Therefore,

g' = 1.38(9.8 m/s²)

<u>g' = 13.5 m/s²</u>

6 0
3 years ago
Explain why bicycles have gears in terms of the force-velocity property of muscle.
denpristay [2]

2 wheels force is put on the back gear to push a larger gear on front . when pedalling on flat force should be applied on middle to smaller size. However when bike reached a terminal force it rider will move to smaller gear and go faster. If bike is going down hill the force of gravity will mean rider can manage the smallest gear as in fastest speed as Force = Mass × Velocity and the impact of gravity means less force is required as the weight of the bike and rider However the opposite it through for uphill as the rider is going against gravity ..weight and gravity will mean the rider will need to go to the larger gear the slower speed.

There are other factors as in wind and slip stream and type of pedals to maximise the force.

6 0
4 years ago
If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c
Lemur [1.5K]

Answer:

\mu_s \geq 0.27

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

f_s=\frac{mv^{2}}{R}

But we know that:

f_s\leq \mu_s N

And the normal force is given by the sum of the forces in the vertical direction:

N-mg=0 \implies N=mg

Finally, we have:

f_s=\frac{mv^{2}}{R}  \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR}  \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27

So, the minimum value for the coefficient of friction is 0.27.

4 0
4 years ago
What are carbon-12, carbon-13, and carbon-14?
denis23 [38]

Answer:

They are all Carbon isotopes.  Carbon 13 has 6 protons and 7 neutrons

Explanation:

Hope this was helpful! :)

4 0
3 years ago
A 1200-kg car initially at rest undergoes constant acceleration for 9.4 s, reaching a speed of 11 m/s. It then collides with a s
Natalka [10]

To solve this problem we will apply the principle of conservation of energy and the definition of kinematic energy as half the product between mass and squared velocity. So,

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Here,

m = Mass

V = Velocity

Replacing,

KE_f = \frac{1}{2} (12000)(11)^2

KE_f = 72600J

Therefore the  final kinetic energy of the two car system is 72.6kJ

8 0
4 years ago
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