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3 years ago

10) Ba + H2O → Ba(OH)2 + H2 How do I balance this ?

Physics

1 answer:

Mashutka [201]3 years ago

4 0

Answer:

That's the answer

Explanation:

If u need explanation I can. In the comments. I hope this satisfies you.

I also hope that u will make this the brainliest answer.

Have a nice day...

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What is refractive index

BARSIC [14]

Answer:

Explanation:

In optics, the refractive index of a material is a dimensionless number that describes how fast light travels through the material. It is defined as where c is the speed of light in vacuum and v is the phase velocity of light in the medium or for short the ratio of the velocity of light in a vacuum to its velocity in a specified medium.

4 0

3 years ago

With their backs against the wall. The cylinder begins to rotate about a vertical axis. Then the floor on which the passengers a

labwork [276]

Answer:

w1 = 4.04 / √r

Explanation:

This exercise should be done using Newton's second law, where the centripetal month acceleration, write the equation for the vertical axis and the radius of rotation

Y Axis

fr - W = 0

fr = W

X axis (radial)

N = m $a_{c}$

The equation for the force of friction is

fr = μ N

Let's replace

μ (m $a_{c}$ ) = mg

Centripetal acceleration is

$a_{c}$ = v² / r

v = wr

$a_{c}$ = w² r

μ w² r = g

w = √(g/μ r)

In order for the trip to be safe, people must not move, so the friction must be static, let's calculate the angular velocity for the extreme values of the friction increase

μ = 0.60

w1 = √ (9.8 / 0.6 r)

w1 = 4.04 / √r

μ = 1.0

w2 = √ (9.8 / 1 r)

w2 = 3.13 / √r

To finish the calculation you need the radius of the cylinder, but for the same radius the safe speed is w1

4 0

3 years ago

Newton’s ______ law of motion states that "an object at rest will stay at rest, and an object in motion will stay in motion, unl

Musya8 [376]

Newton’s <u>first</u> law of motion states that "an object at rest will stay at rest, and an object in motion will stay in motion, unless acted on by an unbalanced force.

It is possible to consider Newton's first law to be the law of inertia. It helped us realise that when a body is at rest, it will remain at rest until an external force is applied to it, or if a body is travelling at a constant speed, it will stay moving until an external force is applied.

Only when net force is applied will a body move from its resting position. An illustration of this law can be seen when a passenger in a car fastens their seat belt. Both stationary and moving objects are covered by this law.

Learn more about force:

brainly.com/question/25239010

#SPJ4

7 0

1 year ago

A ball is still live when

Vera_Pavlovna [14]

It’s both A and B, because technically whenever you drop the ball. It’s called a fumble, and whenever the qb does not catch the snap, the defenders go for it and huddle it so it’s 100% A and B

4 0

3 years ago

You have four identical conducting spheres: A, B, C, and D. In each scenario below, sphere A starts with a charge of -Q, sphere

mash [69]

Answer:

1) Q_c = - ½ Q , 2) Q_c = + ¼ Q , 3) Q_c= 3/8 Q

Explanation:

For this exercise we must use that equal charges repel and charges with different signs attract. When two objects are in contact, the charges are evenly distributed between them.

Scenario 1.

when the two spheres touch the charge -Q is distributed between them, when separating each sphere has a charge = -1/2 Q

as there are no more interacts sphere C its charge is

Q_c = - ½ Q

Scenario 2

when the two spheres touch the charge -Q is distributed between them, when separating each one has a charge

Q_a = Q_d = - ½ Q

now the sphere D and C touch the charge is Q_net = -1/2 Q + Q = + ½ Q

when separating each sphere has half the charge

Q_d = Q_c = + ¼ Q

since sphere C has no more interaction, its charge is

Q_c = + ¼ Q

Scenario 3

A and B touch the net charge is Q_net = - Q + 0 = - Q

when parting

Q_a = Q_b = - ½ Q

now B and D touch, the charge is Q_net = - ½ Q +0 = - ½ Q

when parting

Q_b = Q_d = - ¼ Q

finally C and D touch

the net charge is Q_net = Q- ¼ Q = ¾ Q

when separating each one is left with half the load

Q_c = Q_d = 3/8 Q

Q_c= 3/8 Q

8 0

3 years ago