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4 years ago

11

.______________________ Work is done on an object when the object moves in the same direction in which the force is applied.True

or flase
WE ALL WANT TO NO

1 answer:

suter [353]4 years ago

8 0

Answer:true

Explanation:

Work is done on a object,when the object moves in The same direction in which the force is applied.

Work=force x distance

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A 59.3 kg diver jumps off a board

ser-zykov [4K]

The board is 2.50m high.

Why?

We can calculate how high was the board applying the Law of Conservation of Mechanical Energy. This Law states that the mechanical energy (kinematic and potential) will be conserved during the motion.

It can be described with the following formula:

$E_{M_{1}}=E_{M_{2}}\\\\PE_{1}+KE_{1}=PE_{2}+KE_{2}$

$PE=m*g*h\\KE=\frac{1}{2}m*v^{2}$

At the top of the boar, the kinetic energy is equal to 0.

At the water, the potential energy is equal to 0.

So,

$PE_{1}=KE_{2}\\\\m*g*h=1450J\\\\59.3kg*9.8\frac{m}{s^{2}}*h=1450J\\ \\h=\frac{1450J}{59.3kg*9.8\frac{m}{s^{2}}}=2.50m$

Hence, we have that the board is 2.50m high.

Have a nice day!

6 0

4 years ago

Assume that a 15-kg ball moving at 8 m/s strikes a wall perpendicularly and rebounds elastically at the same speed. What is the

Aleks [24]

I think u should follow the formulae F=MA. So I think the answer is 120N

5 0

3 years ago

I’ve been stuck please help !!

Nat2105 [25]

Answer:

The slope of the position time graph gives the velocity.

Explanation:

The slope of the position time graph gives the value of velocity.

In first graph,

The slope is constant in both the parts but positive . So the velocity is also constant and positive for both the parts. and more than the second part, so the initial velocity is more than the final velocity.

In the second graph,

The slope is constant in both the parts but negative. So, the velocity is constant but negative for both the parts. Initial velocity is more negative than the final velocity.

6 0

3 years ago

A grinding wheel 0.35 m in diameter rotates at 2600 rpm .

ddd [48]

It is calculated that a)The angular velocity of the wheel is 272.13 rad/s,

b)On the edge of the grinding wheel, the linear speed is 47.62 m/s,

and c) On the edge of the grinding wheel, the acceleration is 12958.08 m/s².

Calculation of angular velocity, linear speed & acceleration:

Provided that,

the diameter of the wheel = 0.35 m

So, the radius, r = 0.35/2 = 0.175 m

As 1 revolution = 2π rad

(a)the angular velocity, ω = 2600 rpm = $\frac{2600 * 2\pi }{60}$ rad/s

⇒ω = 272.13 rad/s

So, the angular velocity is 272.13 rad/s.

(b)The linear speed, v = r * ω

⇒v = 0.175 * 272.13

⇒v= 47.62 m/s

(c)The angular acceleration, $a=\frac{v^{2} }{r}$

$a = \frac{(47.62)^{2} }{0.175}$

⇒ $a$ = 12958.08 m/s²

Learn more about angular velocity here:

brainly.com/question/13649539

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6 0

2 years ago

What kind of energy is in a moving skateboard

Ymorist [56]

Answer:

I guess it is kinetic energy

5 0

3 years ago

Read 2 more answers