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3 years ago

the tigers won twice as many football games as they lost. They played 96 games. How many games did they win?

1 answer:

7 0

They lost L games.
They won W games.
W = 2L

W + L = 96, but W = 2L, so

2L + L = 96

3L = 96

L = 32

W = 2L = 2 * 32 = 64

They won 64 games.

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Do you know the answer toPart A: 25% of 50 = Part B: 25% of 60 = Part C: 50% of 60 = Part D: 75% of 60 = Part E: 75% of 30 = Par

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Answer:

Part A: 25% of 50 = 12.5

Part B: 25% of 60 = 15

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Step-by-step explanation:

To find - Do you know the answer to

Part A: 25% of 50 =

Part B: 25% of 60 =

Part C: 50% of 60 =

Part D: 75% of 60 =

Part E: 75% of 30 =

Part F: 100% of 22.5 =

Part G: 10% of 22.5 =

Part H: 50% of 45.7 =

Proof -

Part A :

25% of 50 = $\frac{25}{100} *50$ = $\frac{1}{4}*50$ = 12.5

⇒25% of 50 = 12.5

Part B :

25% of 60 = $\frac{25}{100} *60$ = $\frac{1}{4}*60$ = 15

⇒25% of 60 = 15

Part C :

50% of 60 = $\frac{50}{100} *60$ = $\frac{1}{2}*60$ = 30

⇒50% of 60 = 30

Part D :

75% of 60 = $\frac{75}{100} *60$ = $\frac{75}{10}*6$ = 45

⇒75% of 60 = 45

Part E :

75% of 30 = $\frac{75}{100} *30$ = $\frac{75}{10}*3$ = 22.5

⇒75% of 30 = 22.5

Part F :

100% of 22.5 = $\frac{100}{100} *22.5$ = 22.5

⇒ 100% of 22.5 = 22.5

Part G :

10% of 22.5 = $\frac{10}{100} *22.5$ = 2.25

⇒ 10% of 22.5 = 2.25

Part H :

50% of 45.7 = $\frac{50}{100} *45.7$ = $\frac{1}{2}*45.7$ = 22.85

⇒50% of 45.7 = 22.85

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