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Over [174]
3 years ago
10

What is the area of this triangle? Enter your answer as a decimal in the box. Round only your final answer to the nearest hundre

dth. ft² The figure contains a triangle. One side is 2.7 feet. A second side is 3.4 feet. The angle between the given sides is 40 degrees.
Mathematics
2 answers:
nika2105 [10]3 years ago
6 0

Answer:

Area of the triangle \simeq 5.9 sq. ft. .

Step-by-step explanation:

Length of two sides of the triangle are, 2.7 feet and 3.4 feet and the angle between them is 40° .

So, the area of the triangle is given by,

2.7 \times 3.4 \times \sin {40^{\circ}}  sq. ft.

\simeq 5.9 sq. ft.

wolverine [178]3 years ago
5 0

<u>Answer:</u>

The area of triangle is 3.42 \mathrm{ft}^{2}

<u>Explanation:</u>

We are given two sides of a triangle and their including angle.

The two given sides of a triangle are , one is 2.7 ft and other is 3.4 ft

And the including angle is given to be 40°

The formula to find area of triangle when two sides and their including angle is given is-

=\frac{a b \sin \theta}{2}

where a and b are two sides and θ is the including angle.

Substituting the given values,  

Area =\frac{2.7 \times 3.4 \times \sin 40^{\circ}}{2}

 = \frac{2.7 \times 3.4 \times 0.74}{2}

= 3.42

Hence 3.42 \mathrm{ft}^{2} is the area of triangle.

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From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0
3 years ago
X+a=3/4 I don't know how to solve this and I need someone to help explain it to me.
Aneli [31]
I think you should Subtract
a
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3 years ago
What 3 numbers when multiplied, equals to 4,000? <br><br> Please help! Will give Brainliest!
vlada-n [284]

Answer:

you can do (500)(4) x 2

Step-by-step explanation:

500 x 4 = 2000

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7 0
3 years ago
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Mamont248 [21]

7-2c= c - 2 this is the answer



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scZoUnD [109]

Answer:

351 carrots

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13 = 1 tens + 3 units

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2 years ago
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