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Lunna [17]
3 years ago
6

Is segment ST tangent to circle P1

Mathematics
1 answer:
malfutka [58]3 years ago
7 0

Answer:

B . Yes

Step-by-step explanation:

Recall: a tangent of a circle is perpendicular to the radius of a circle, forming a right angle at the point of tangency.

Therefore, if segment ST is tangent to circle P, it means that m<T = 90°, and ∆PST is a right triangle.

To know if ∆PST is a right triangle, the side lengths should satisfy the Pythagorean triple rule, which is:

c² = a² + b², where,

c = longest side (hypotenuse) = 37

a = 12

b = 35

Plug in the value

37² = 12² + 35²

1,369 = 1,369 (true)

Therefore we can conclude that ∆PST is a right triangle, this implies that m<T = 90°.

Thus, segment ST is a tangent to circle P.

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Answer:

we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

Step-by-step explanation:

Considering the equation

3y\:+\:2\:=\:2x\:-\:5

  • Putting (-5,2) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(2\right)\:+\:2\:=\:2\left(-5\right)\:-\:5

8=-15         ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (0,-5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(-5\right)\:+\:2\:=\:2\left(0\right)\:-\:5

-13=-5       ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (5,1) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(1\right)+\:2\:=\:2\left(5\right)-\:5

5\:=-5          ∵ L.H.S ≠ R.H.S

FALSE

  • Putting (7,5) in the equation

3y\:+\:2\:=\:2x\:-\:5

3\left(5\right)+\:2\:=\:2\left(7\right)-\:5\:\:

17=9          ∵ L.H.S ≠ R.H.S

FALSE

From the above calculations, we determine that none of the ordered pair is a solution of  3y\:+\:2\:=\:2x\:-\:5  as none of the ordered pairs satisfy the equation.

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