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2 years ago

I need help plz :( i will give brainlist

Mathematics

1 answer:

Genrish500 [490]2 years ago

5 0

Answer:

it's C because the slopes are the same but the y intercepts are different

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Dentify all the pairs of vertical angles in the figure. Pair#1: Pair#2

Brilliant_brown [7]

Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious

3 0

3 years ago

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is a separable differential equation. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$

Therefore,

$\frac{1}{r} \ln |rA+P| = t+c$

Multiply both sides by $r.$

$\ln |rA+P| = rt+c_1, \quad c_1 := rc$

By taking exponents, we obtain

$e^{\ln |rA+P|} = e^{rt+c_1} \implies |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}$

Isolate $A$ .

$rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}$

Since $A = 0$ when $t=0$ , we obtain an initial condition $A(0) = 0$ .

We can use it to find the numeric value of the constant $c$ .

Substituting $0$ for $A$ and $t$ in the equation gives

$0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P$

Therefore, the solution of the given differential equation is

$A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)$

4 0

3 years ago

The slope of the line that passes through the point (17,20) and (1,-8) is

AlladinOne [14]

Answer:

y = m x + b standard form of equation for straight line\

m = (y2 - y1) / (x2 - x1) = (20 - -8) / 17 - 1) = 28 / 16

m = 7 / 4

8 0

3 years ago

Classify Angle 5 & Angle 6 by choosing the correct term from the choices below.

vampirchik [111]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

In the given figure, the angles 5 and 6 form Vertical opposite angle pair.

so, correct choice is Vertical

6 0

2 years ago

Change 1.234 to a percent

Nookie1986 [14]

Answer:

1.234 / 100 = 0.01234

Therefore;

0.01234 x purchase price = profit

same as

purchase price / 1.01234 = profit

formula Cost or initial Price x ( % / 100 )

and show % as a whole number ie ) 1.234 / 100 = 0.01234

= cip x 1.01234 = profit

When we divide by 100 the 1 moves two spaces to the right.

when we have to find initial price from given sale price

we deduct given percentage from 100% and use that to multiply with instead omitting the 1 if its depreciating or adding the 1 if its original price ticket.

6 0

3 years ago

I need help plz :( i will give brainlist​

I need help plz :( i will give brainlist