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ololo11 [35]
2 years ago
9

I need help plz :( i will give brainlist​

Mathematics
1 answer:
Genrish500 [490]2 years ago
5 0

Answer:

it's C because the slopes are the same but the y intercepts are different

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Dentify all the pairs of vertical angles in the figure.<br><br> Pair#1:<br><br> Pair#2
Brilliant_brown [7]
Ok so the only ones that we know for sure are 4 = 1, 6=8, 7=9 and you can’t really do all that much with 2,3,5 because it’s not as obvious
3 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
The slope of the line that passes through the point (17,20) and (1,-8) is
AlladinOne [14]

Answer:

y = m x + b      standard form of equation for straight line\

        m = (y2 - y1) / (x2 - x1) = (20 - -8) / 17 - 1) = 28 / 16

        m = 7 / 4

8 0
3 years ago
Classify Angle 5 &amp; Angle 6 by choosing the correct term from the choices below.
vampirchik [111]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

In the given figure, the angles 5 and 6 form Vertical opposite angle pair.

so, correct choice is Vertical

6 0
2 years ago
Change 1.234 to a percent
Nookie1986 [14]

Answer:

1.234 / 100  =  0.01234

Therefore;

0.01234 x purchase price = profit

same as

purchase price  / 1.01234  = profit

formula    Cost or initial Price   x    (  % / 100 )

and show % as a  whole number ie ) 1.234 / 100 = 0.01234

= cip x 1.01234 = profit

When we divide by 100 the 1 moves two spaces to the right.

when we have to find initial price from given sale price

we deduct given percentage from 100% and use that to multiply with instead omitting the 1 if its depreciating or adding the 1 if its original price ticket.

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