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ss7ja [257]
3 years ago
10

What is the slope of the line represented by the equation ?

Mathematics
1 answer:
Citrus2011 [14]3 years ago
7 0
The slope of the equation is 1/2
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The measure of angle S is 65 degrees.
suter [353]

Answer:

A. 115°

Step-by-step explanation:

180° - 65° = 115°

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F(-2), f(x)=x^2-3x+2
Evgen [1.6K]
The answer would be 12
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There are 2 girls and 3 boys on a camping trip. What is the ratio of girls<br> to boys on the trip?
vodka [1.7K]

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2/3

Step-by-step explanation:

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3 years ago
Si -x+y+z=75, entonces -(x+3)+(y-5)+(z-6)=
jenyasd209 [6]

Answer:

67

Step-by-step explanation:

● -(x + 3) + (y - 5) + (z - 6)

● -x - 3 + y - 5 + z - 6

● (-x + y + z) + (3 -5 -6)

● 75 + 3 - 11

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8 0
3 years ago
Find the minimum and maximum value of the function on the given interval by comparing values at the critical points and endpoint
Kitty [74]

Answer:

maximum: y = 1

minimum: y = 0.

Step-by-step explanation:

Here we have the function:

y = f(x) =  √(1 + x^2 - 2x)

we want to find the minimum and maximum in the segment [0, 1]

First, we evaluate in the endpoints, which are 0 and 1.

f(0)  =√(1 + 0^2 - 2*0) = 1

f(1) = √(1 + 1^2 - 2*1) = 0

Now let's look at the critical points (the zeros of the first derivate)

To derivate our function, we can use the chain rule:

f(x) = h(g(x))

then

f'(x) = h'(g(x))*g(x)

Here we can define:

h(x) = √x

g(x) = 1 + x^2 - 2x

Then:

f(x) = h(g(x))

f'(x)  =  1/2*( 1 + x^2 - 2x)*(2x - 2)

f'(x) = (1 + x^2 - 2x)*(x - 1)

f'(x) = x^3 - 3x^2 + x - 1

this function does not have any zero in the segment [0, 1] (you can look it in the image below)

Thus, the function does not have critical points in the segment.

Then the maximum and minimum are given by the endpoints.

The maximum is 1 (when x = 0)

the minimum is 0 (when x = 1)

7 0
3 years ago
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