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maw [93]
3 years ago
9

Determine whether these functions are invertible. Find inverses of the invertible functions.

Mathematics
1 answer:
Flauer [41]3 years ago
6 0
B) is not invertible, while the others are.
a) The inverse is x+2
c) The inverse is \sqrt{x}
d) The inverse is \sqrt[3]{x}
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Annie and him are taking turns driving on their trip. On one day they drove a total of 420 miles. Annie drove 3 times farther th
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1,260 miles all you have to do is 420x3 because Annie drove 3 times faster.
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What is the solution to the system of equations graphed below?
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a

Step-by-step explanation:

the two lines intercept at 1,-2

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3 years ago
Please answer this correctly without making mistakes
tankabanditka [31]

Answer:

263.76

Step-by-step explanation:

Assuming the shaded area is the yellow area all we must do is find the area of the small circle and subtract it from the larger circle.

To do this we can use the area of a circle equation:

A=\pi r^2

first we need to find the radius of the large circle which is simply 4+6= 10

so the area would be:

A=\pi 10^2\\A=100\pi

then we find the area of the small circle is

A=4^2\pi \\A=16 pi

next we evaluate:

100\pi -16\pi =84\pi

Then replace pi with 3.14:

84 · 3.14 = 263.76

And you have your answer!

Hope this helps!

8 0
3 years ago
When an object is droppednbsp on a certain earth dash like planet comma on a certain earth-like planet, the distance it falls in
ANTONII [103]

Answer:

(a) s(44) = 3.52*10^{6}ft

(b) v(44) = 10*x^{5} ft/s

(c) a(44) = 3636ft/s^{2}

Step-by-step explanation:

s(t) = 1818t^{2}

(a) when t = 44sec

s(44) = 1818(44^{2}) = 1818(1936)\\ \\s(44) = 3519648ft

s(44) ≅ 3520000=3.52*10^{6}ft

(b) How fast the hammer is traveling i.e. the speed of the hammer.

To find speed, we differentiate the distance s(t) with respect to time, t

speed,v=\frac{ds(t)}{dt}=\frac{d}{dt}(1818t^{2})   \\\\v = 1818*2t^{2-1}= 1818*2t\\ \\v = 3636t

at t = 44sec,

v = 3636*44=159984ft/s

v ≅ 160000ft/s = 1.6*10^{5}ft/s

(c) The hammer's acceleration can be obtained by differentiating the speed v(t) with respect to time, t

acceleration, a = \frac{dv}{dt}=\frac{d}{dt}(3636t)\\  \\a = 3636*1= 3636\\\\a = 3636ft/s^{2}

There's no need to substitute t = 44sec because the acceleration is independent of time.

3 0
3 years ago
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