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Andreas93 [3]
3 years ago
12

A cylindrical cork (area A, length L, density pc) is floating in a liquid of density Pw with only a part of its length L submerg

ed in the liquid. If the cork is pushed down by a small distance Xm and then let go, what is the frequency f of the subsequent bobbing simple harmonic motion? Express your answer in terms of the quantities Pc, Pw, A, L, and g.
Physics
1 answer:
8_murik_8 [283]3 years ago
5 0

Answer:

Explanation:

Given

\rho _c=density of cork

\rho _w=density of water

L=Length of cylinder

If initially x length is under water

At equilibrium

\rho _wAxg-\rho _cALg=0

After giving X_m push

\rho _wAg(x+X_m)-\rho _cALg=\rho _cALa

where a  is acceleration of system

and a=\frac{\mathrm{d^2} X_m}{\mathrm{d} t^2}

\rho _wAgX_m=\rho _cAL\frac{\mathrm{d^2} X_m}{\mathrm{d} t^2}

\frac{\mathrm{d^2} X_m}{\mathrm{d} t^2}=\frac{\rho _wAg}{\rho _cAL}

thus \omega ^2=\frac{\rho _wg}{\rho _cL}

thus \omega =\sqrt{\frac{\rho _wg}{\rho _cL}}

and 2\pi f=\omega

f=\frac{\sqrt{\frac{\rho _wg}{\rho _cL}}}{2\pi }

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mojhsa [17]
Physical change = changes the physical properties (more commonly known as it's look)
Chemical change = changes the chemical properties into an entire new chemical form
Examples of physical change would be melting ice cubes or sugar cubes.
Examples of chemical change would be cooking eggs or burning paper because you're changing its chemical properties.
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3 years ago
A rectangular coil with 50 turns of conducting wire and a total resistance of 10.0 Ω initially lies in the yz-plane at time t =
castortr0y [4]

Answer:

a) 43.20V

b) 2.71W/s

c) 40.25s

d) 7.77Nm

Explanation:

(a) The emf of a rotating coil with N turns is given by:

emf=NBA\omega sin(\omega t)

N: turns

B: magnitude of the magnetic field

A: area

w: angular velocity

the emf max is given by:

emf_{max}=NBA\omega=(50)(1.80T)(0.200m*0.100m)(24.0rad/s)\\\\emf_{max}=43.20V

(b) the maximum rate of change of the magnetic flux is given by:

\frac{d\Phi_B}{dt}=\frac{d(A\cdot B)}{dt}=\frac{d}{dt}(ABcos\omega t)=AB\omega sin(\omega t)\\\\\frac{d\Phi_B}{dt}_{max}=(\pi(0.200*0.100))(1.80T)(24.0rad/s)=2.71\frac{W}{s}

(c) emf(t=0.050s)=(50)(1.80T)(0.200m*0.100m)(24rad/s)sin(24.0rad/s(0.050s))\\\\emf(t=0.050s)=40.26V

(d) The torque is given by:

\tau=NABIsin\theta\\\\NAB\omega=emf_{max}\\\\\tau=\frac{emf_{max}}{\omega}\frac{emf_{max}}{R}\\\\\tau=\frac{(43.20V)^2}{(24.0rad/s)(10.0\Omega)}=7.77Nm

3 0
3 years ago
imagine that 501 people are present in a movie theater of volume 8.00 x10^3 that is sealed shut so no air can escape. Each perso
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Answer:

The temperature of air will increase by \Delta T=41044.967\ K

Explanation:

Given:

  • no. of person in a theater, n=501
  • volume of air in the theater, V=8\times 10^3\ m^3
  • rate of heat given off by each person, P=110\ J.s^{-1}
  • duration of movie, t=2\ hr=7200\ s
  • initial pressure in the theater, p_i=1.01\times 10^5\ Pa
  • initial temperature in the theater, T_i=20+273=293\ K
  • specific heat capacity of air at the given conditions, c=1.0061\ J.kg^{-1}.K^{-1}

<u>The total quantity of heat released by the total people in the theater during the movie:</u>

Q=n.P.t

Q=501\times 110\times 7200

Q=396792000\ J

<u>Form the relation of heat capacity:</u>

Q=m.c.\Delta T

∵p_i.V=m.R.T

Q=(\frac{p_i.V}{R.T}) \times c\times (T_f-T_i)

396792000=(\frac{1.01\times 10^5\times 8\times 10^3}{287\times 293}) \times 1.0061\times (T_f-293)

T_f=41337.967\ K

Change in temperature of air:

\Delta T=41044.967\ K

8 0
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Answer:

Use a pot??

Explanation:

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85+5=90 :DD
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Good lessons.
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