Answer:
3.974 Joule
Explanation:
Diameter of ring = 7.7 cm
a = Distance from the center = d/2 = 3.85 cm = 0.0385 m
Q = Charge = 5 mC
q = Charge to move = 3.4 mC
k = Coulomb constant = 9×10⁹ Nm²/C²
Work done will be equal to Potential energy when mass is at center
∴ Work to move a tiny 3.4 mC charge from very far away to the center of the ring is 3.974 Joule
hope it helps:)
Explanation:
A galvanometer is converted into an ammeter by connecting a low resistance in parallel with the galvanometer. This low resistance is called shunt resistance S. The scale is now calibrated in ampere and the range of ammeter depends on the values of the shunt resistance.
Answer:
False
Explanation:
The current flowing through a circuit can be computed by using Ohm's law:
where
V is the voltage of the battery
Req is the total resistance of the circuit
Let's now compare the two situations. Let's call R the resistance of each resistor (since they are identical, they have same resistance, R)
- Series configuration: in this case, the total resistance of the circuit is given by
So the current through the circuit is
(1)
- Parallel configuration: in this case, the total resistance of the circuit is given by
So the current through the circuit is
(2)
By comparing (1) and (2), we see that the current in the parallel configuration is greater than in the series configuration:
therefore, the correct answer is false.
As the gas absorbs heat, the sounds he hears become softer. This is because the pressure of the neon gas inside the container increases when the gas gets warmer, the walls of the container become tighter and stiffer, and it's harder for them to vibrate.
Answer:
Explanation:
Given
mass of projectile
initial horizontal speed
height
Considering vertical motion
velocity gained by projectile during 26.7 m motion
v=final velocity
u=initial velocity
a=acceleration
s=displacement
Horizontal velocity will remain same as there is no acceleration
final velocity
Initial kinetic Energy
Final Kinetic Energy
Work done by all the force is equal to change in kinetic Energy of object
Work done by gravity is