Waxing gibbous
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Yes yes ! How right you are ! Truer words were never spoken.
F=ma
Force=mass*acceleration
So plug in the values
Hint: the force would be measured in newtons
Answer:
The final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
Explanation:
Let us consider east as positive direction and west as negative direction .
Given
mass of puck 1 , 
mass of puck 2 , 
initial speed of puck 1 , 
initial speed of puck 2 , 
Final speed of puck 1 and puck 2 be
respectively
Apply conservation of linear momentum

=>
=>
-----(A)
Since collision is perfectly elastic , coefficient restitution e=1

=>
------(B)
From equation (A) and (B)

and 
Thus the final speed of puck 1 is 0.739 m/s towards west and puck 2 is 2.02 m/s towards east .
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