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svetoff [14.1K]

4 years ago

11

You push a 4.9 kg block against a horizontal spring, compressing the spring by 16 cm. then you release the block, and the spring

sends it sliding across a tabletop. it stops 77 cm from where you released it. the spring constant is 220 n/m. what is the coefficient of kinetic friction between the block and the table?

1 answer:

In-s [12.5K]4 years ago

4 0

A boiling pot of water (the water travels in a current throughout the pot), a hot air balloon (hot air rises, making the balloon rise) , and cup of a steaming, hot liquid (hot air rises, creating steam) are all situations where convection occurs.
Read more on Brainly.com - brainly.com/question/1581851#readmore

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Which statement descThe image shows the right-hand rule being used for a current-carrying wire.

Makovka662 [10]

Answer:

The second option.
When the current flows up the wire, the magnetic field flows out on the left side of the wire and in on the right side of the wire.

Explanation:

The first figure that I copy here with is the figure corresponding to this question.

The thumb is pointing upward.

The rule is that the thumb aims to the direction of the flow of current and the other fingers give the field lines.

The second figure that I attach is a free image from internet and it shows the direction of both the current and the fiedl lines.

So, the conclusion is that the current goes upward the wire and the field lines go out of the paper (screen) for the points to the left of the wire and in on the right side of the wire.

4 0

4 years ago

Read 2 more answers

What magnification will be produced by a lens of power –4.00 D (such as might be used to correct myopia) if an object is held 43

kiruha [24]

Answer:

The magnification is $m = 0.3674$

Explanation:

From the question we are told that

The power of the lens is $P = -4.00 D(dioptre)$

Generally $1 dioptre = 1 \ meter$

The object distance is $u = -43 \ cm$ the negative sign is because the distance is measured in the opposite direction of incident light (i.e away )

Generally the focal length is mathematically represented as

$f = \frac{1}{P}$

=> $f = \frac{1}{4.00 }$

=> $f = 0.25 \ m$

converting to cm

=> $f = 0.25 \ m = 0.25 * 100 = 25 \ cm$

Generally from lens equation we have that

$\frac{1}{f} +\frac{1}{v} -\frac{1}{u}$

=> $\frac{1}{25} +\frac{1}{v} -\frac{1}{-43}$

=> $v = -15.8 \ cm$

Generally the magnification is mathematically represented as

$m = \frac{v}{u}$

=> $m = \frac{- 15.8}{-43}$

=> $m = 0.3674$

6 0

3 years ago

How could you design a system of ramps to get a marble to land in a cup on an elevated platform

Vedmedyk [2.9K]

Answer

use a steep ramp

Explanation:

3 0

3 years ago

A ball is thrown straight up from the edge of a 15 foot balcony with initial velocity 40 feet/sec. how high will the ball travel

NeTakaya

Hello
The initial height of the ball is $S_i = 15~ft = 4.6~m$ , while the initial velocity is $v_i = 40ft/s = 12.2~m/s$ .
This is a uniformly accelerated motion, where the acceleration is the gravitational acceleration: $a=-9.8~m/s^2$ , where the negative sign means that the acceleration points downwards.
We can proceed in two steps:

1) First of all, we calculate the time the ball needs to reach the maximum height. At the point of maximum height, the velocity is zero: $v_f = 0m/s$ .
We can use the formula
$a= \frac{v_f-v_i}{\Delta t}$
To find the time:
$\Delta t= \frac{v_f-v_i}{a} = 1.2 s$

2) At this point, we can calculate the total height reached by the ball after this time, i.e. the maximum height:
$S=S_i+v_i \Delta t+ \frac{1}{2} a (\Delta t)^2 =$
$= 4.6~m+(12.2~m/s)(1.2~s)+ \frac{1}{2}(-9.8~m/s^2)(1.2~s)^2 = 12.1~m$

3 0

3 years ago

Someone plz help for a brainliest

d1i1m1o1n [39]

Okay, i worked on this last year, a transverse wave is a wave that vibrates in the direction of its propagation, and a compression wave is a wave that travels closer together!

3 0

3 years ago