Question

A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67 m, what is the spring constant?

Answer 1

Answer:

6.22 N/m

Explanation:

F=xk  Making k the subject of the formula then

$k=\frac {F}{x}$

But since the applied force F is mg then we substitute mg with F is the formula hence

$k=\frac {mg}{x}$

Converting the given mass from g to Kg, we divide it by 1000 hence m= 0.425 and taking g as 9.81 and substituting x with 0.67 m then

$k=\frac {0.425\times 9.81}{0.67 m}=6.222761194\ N/m\approx 6.22\ N/m$