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postnew [5]
3 years ago
12

A spring is hung vertically with a 425g mass attached to it. The mass is at rest. If the mass causes the spring to stretch 0.67

m, what is the spring constant?
Physics
1 answer:
ivann1987 [24]3 years ago
4 0

Answer:

6.22 N/m

Explanation:

F=xk  Making k the subject of the formula then

k=\frac {F}{x}

But since the applied force F is mg then we substitute mg with F is the formula hence

k=\frac {mg}{x}

Converting the given mass from g to Kg, we divide it by 1000 hence m= 0.425 and taking g as 9.81 and substituting x with 0.67 m then

k=\frac {0.425\times 9.81}{0.67 m}=6.222761194\ N/m\approx 6.22\ N/m

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