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kiruha [24]
4 years ago
12

Pea plant clones are given different amounts of water for a three-week period. The first pea plant receives 400 milliliters a da

y. The second pea plant receives 200 milliliters a day. The third pea plant receives 100 milliliters a day. The fourth pea plant does not receive any extra water: the plant only receives natural ways of receiving water. The heights of the pea plants are recorded daily.
IV ________________________________


DV_______________________________
Physics
1 answer:
musickatia [10]4 years ago
5 0

Answer:

3

Explanation:

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The central atom in a lewis structure tends to be the ____________ atom.
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Answer:

The central atom in a lewis structure tends to be the least electronegative atom.

Explanation:

Lewis structures show each atom and its position in the structure of the molecule using its chemical symbol.

In Lewis structure, the central atom tends to be the least electronegative atom. Usually the central atom will be the one that has the most unpaired valence electrons or  least electronegative.

Therefore, the best phrase that completes the sentence is "least electronegative".

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A cube 6.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through a
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To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.

For the particular case of the Cube with equal sides its volume is determined by

V_c = l^3

V_c = 6^3 = 216cm^3

In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say

V_d = \pi r^2*l

V_d = \pi (\frac{2}{2})^2*6

V_d = 6\pi cm^3

In this way the net volume would be

\Delta V = V_c-V_d

\Delta V = 216cm^3-6\pi cm^3

\Delta V = 197.15cm^3 = 197.15*10^{-6}m^3

We need to find the mass, but we have the Weight and Gravity so from Newton's second Law

F= mg

m = \frac{F}{g}

m = \frac{6.6}{9.8}

m = 0.673kg

PART A) From the relation of density as a unit of mass and volume we have to

\rho = \frac{m}{V}

\rho = \frac{0.673}{197.15*10^{-6}}

\rho = 3413.64kg/m^3

PART B) To find the weight of the cube then we apply the ratio of

W = mg

W = V\rho g

W = (216*10^{-6})(3413.64)(9.8)

W = 7.22N

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