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anyanavicka [17]
3 years ago
11

Bone with a latticework structure is called

Physics
1 answer:
malfutka [58]3 years ago
7 0
Spongy or the cancellous bone is the bone with lattice work structure
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A 72-kg man stands on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.
Shalnov [3]

Answer:

Explanation:

During the first .8 s , the elevator is under acceleration . It starts from initial velocity u = 0 , final velocity v = 1.2 m /s , time = .8 s

v = u + at

1.2 = 0 +  .8 a

a = 1.2 / .8

= 1.5 m /s²

During the acceleration in upward direction , let reaction force of ground on man be R .

Net force on man = R - mg

Applying Newton's 2 nd law

R - mg = ma

R = m ( g + a )

= 72 ( 9.8 + 1.5 )

= 813.6 N .

This reaction force will be measured by spring scale , so reading of spring scale will be 813.6 N .

3 0
2 years ago
If two balls have the same volume,
Lena [83]

Here, we are required to find the relationship between balls of different mass(a measure of weight) and different volumes.

  • 1. Ball A will have the greater density
  • 2. Ball C and Ball D have the same density.
  • 3. Ball Q will have the greater density.
  • 4. Ball X and Y will have the same density

The density of an object is given as its mass per unit volume of the object.

Mathematically;.

  • Density = Mass/Volume.

For Case 1:

  • Va = Vb and Ma = 2Mb
  • D(b) = (Mb)/(Vb) and D(a) = 2(Mb)/Vb
  • Therefore, the density of ball A,
  • D(a) = 2D(b).
  • Therefore, ball A has the greater density.

For Case 2:

  • Vc = 3Vd,

  • Vd = (1/3)Vc

  • Md = (1/3)Mc

  • D(c) = (Mc)/(Vc) and D(d) = (1/3)Md/(1/3)Vd

  • D(c) = D(d).

  • Therefore, ball C and D have the same density

For Case 3:

  • Vp = 2Vq and Mp = Mq
  • D(p) = (Mq)/2(Vq) and D(q) = (Mq)/Vq
  • Therefore, the density of ball P is half the density of ball Q
  • Therefore, ball Q has the greater density.

For case 4:

  • Mx = (1/2)My
  • Vx = Vy

Therefore, Ball X and Ball Y have the same density.

Read more:

brainly.com/question/18110802

8 0
2 years ago
Why must objects be cooled before their mass is determined on a sensitive balance?
zubka84 [21]
Objects should be cooled before their mass is determined on a sensitive balance because it could damage the balance. Also, because it would give you wrong reading of the mass. Hot objects would warm the air around it. A warm air would expand and would produce convection as it rises causing to give the object a mass that is less than the actual. Another reason would be it would cause instability in the readings, the mass would fluctuate every now and then due to the convection currents around the object. It is always recommended to weigh the masses of objects that are in room temperature.
5 0
3 years ago
write a motivational speech to someone who wants to become a scientist please write this as it is for kids :) PLEASEE HELP!!!!
Gekata [30.6K]

Answer:

A motivational speech for a to be scientist. Crazy experiments and more you have the right to be whatever you adore. Your young yet strong everything will come along. I believe in you and so should you since your becoming a scientist you’ll acquire it soon. You’ll discover new things and sight to see when you become a scientist make sure to call me. :)

Explanation:

Hope it’s good I made up a couple words that rhyme good luck!

6 0
3 years ago
Read 2 more answers
3. A ray of light consisting of blue light (wavelength 480 nm) and red light (wavelength 670 nm) is incident on a thick piece of
Alex Ar [27]

Answer:

The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.

Explanation:

Given that,

The respective indices of refraction for the blue light and the red light are 1.4636 and 1.4561.

A ray of light consisting of blue light (wavelength 480 nm) and red light (wavelength 670 nm) is incident on a thick piece of glass at 80 degrees.

We need to find the angular separation between the refracted red and refracted blue beams while they are in the glass.

Using Snell's law for red light as :

n_1\sin\theta_1=n_2\sin\theta_2\\\\\theta_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta_2=\sin^{-1}((\dfrac{1}{1.4561})\sin(80))\\\\\theta_2=42.555

Again using Snell's law for blue light as :

n_1\sin\theta_1=n_2\sin\theta'_2\\\\\theta'_2=\sin^{-1}((\dfrac{n_2}{n_1})\sin\theta_1)\\\\\theta'_2=\sin^{-1}((\dfrac{1}{1.4636 })\sin(80))\\\\\theta'_2=42.283

The angular separation between the refracted red and refracted blue beams while they are in the glass is 42.555 - 42.283 = 0.272 degrees.

7 0
3 years ago
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