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anyanavicka [17]
3 years ago
11

Bone with a latticework structure is called

Physics
1 answer:
malfutka [58]3 years ago
7 0
Spongy or the cancellous bone is the bone with lattice work structure
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If you have a 1.0 m aqueous solution of NaCl, by how much will it increase the water’s boiling point, if KB = 0.512 °C/m? In oth
fgiga [73]

<u>Answer:</u> The elevation in boiling point is 1.024°C.

<u>Explanation:</u>

To calculate the elevation in boiling point, we use the equation:

\Delta T_b=ik_b\times m

where,

i = Van't Hoff factor = 2 (for NaCl)

\Delta T_b = change in boiling point  = ?

k_b = boiling point constant = 0.512^oC/m

m = molality = 1.0 m

Putting values in above equation, we get:

\Delta Tb=2\times 0.512^oC/m\times 1.0m\\\\\Delta Tb=1.024^oC

Hence, the elevation in boiling point is 1.024°C.

5 0
3 years ago
how much chemical energy must be supplied to a car engine if we want it to produce 5000J of kinetic energy and it is 45% efficie
vagabundo [1.1K]

Here i state the conservation of energy rule and use that to justify my answer. I showed how to manipulate percentages to get the final answer of 11000J (2sf). Hope I'm right xx

3 0
3 years ago
A hockey pick sliding along a frictional surface strikes a box at rest, after the collision the two objects stick together and m
Hitman42 [59]

Answer:

Explanation:

Option a is correct  

If puck and pick constitute a system then the momentum of the system is conserved but not this may not be valid for the puck .

Option e is correct

If puck and pick is the system then momentum is conserved but because of the presence of friction, mechanical energy is not conserved.

Friction will cause the energy to dissipate in heat.

       

5 0
3 years ago
What is the difference between mutual flux, leakage flux and magnetizing flux<br> ​
Lemur [1.5K]

In simple words, flux can be stated as the rate of flow of a fluid, radiant energy, or particles across a given area.

<u>Explanation:</u>

<u>Mutual Flux:</u>

  • The magnetic lines present in among two magnets or solenoid is mutual flux.
  • These are the lines in which the attraction and repulsion happens.
  • The SI unit of mutual flux is the Henry

<u>Leakage Flux:</u>

  • In simple words, it can be stated as  the magnetic flux which does not follow the specially designed way in a magnetic circuit.
  • Leakage flux in the induction motor takes spot due to current runs through the essence of the induction motor.
  • The SI unit of Leakage flux is the Weber

<u>Magnetizing flux</u>

  • Magnetic flux is an analysis of the entire magnetic field which moves in a given field
  • In simple words can be defined as the Magnetic flux is what generates the field around a magnetic material.
  • The SI unit of magnetic flux is the Weber
3 0
3 years ago
A cubical box measuring 1.29 m on each side contains a monatomic ideal gas at a pressure of 2.0 atm How much thermal energy do t
Marrrta [24]

Answer:

a) U = 652.545\,kJ, b) v \approx 659.568\,\frac{m}{s}

Explanation:

a) According to the First Law of Thermodinamics, the system is not reporting any work, mass or heat interactions. Besides, let consider that such box is rigid and, therefore, heat contained inside is the consequence of internal energy.

Q = U

The internal energy for a monoatomic ideal gas is:

U = \frac{3}{2} \cdot n \cdot R_{u} \cdot T

Let assume that cubical box contains just one kilomole of monoatomic gas. Then, the temperature is determined from the Equation of State for Ideal Gases:

T = \frac{P\cdot V}{n\cdot R_{u}}

T = \frac{(202.65\,kPa)\cdot(1.29\,m)^{3}}{(1\,kmole)\cdot(8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K} )}

T = 52.325\,K

The thermal energy contained by the gas is:

U = \frac{3}{2}\cdot (1\,kmole)\cdot (8.314\,\frac{kPa\cdot m^{3}}{kmole\cdot K})\cdot (52.325\,K)

U = 652.545\,kJ

b) The physical model for the cat is constructed from Work-Energy Theorem:

U = \frac{1}{2}\cdot m_{cat} \cdot v^{2}

The speed of the cat is obtained by isolating the respective variable and the replacement of every known variable by numerical values:

v = \sqrt{\frac{2 \cdot U}{m_{cat}}}

v = \sqrt{\frac{2\cdot (652.545 \times 10^{3}\,J)}{3\,kg} }

v \approx 659.568\,\frac{m}{s}

3 0
3 years ago
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