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Amiraneli [1.4K]
3 years ago
15

A regular hexagon has an apothem of 2 and a side length of 4 /3/3 its area is

Mathematics
1 answer:
Ne4ueva [31]3 years ago
5 0
A hexagon can be considered to be  6 triangles with a common vertex.
Area of 1 of the triangle = 1/2 * 2 * side length

Area of whole hexagon is 6 times this.
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Brainliest to who answers :>
rusak2 [61]

Answer:

L is not valid.

Step-by-step explanation:

For any triangle, the sum of the two legs must be greater than the hypotenuse. Otherwise the two legs would not be long enough to touch.

7 0
2 years ago
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Identify the expression as a numerical expression or variable expression I•8
user100 [1]

A is the answer because the number 8 is a constant. and the multiplication sign is the operator.

6 0
3 years ago
What is 3/4 + 3.3 - 1 1/2?
guapka [62]

Answer:

2.55

Step-by-step explanation:1

Convert 1121\frac{1}{2}1​2​​1​​ to improper fraction. Use this rule: abc=ac+bca \frac{b}{c}=\frac{ac+b}{c}a​c​​b​​=​c​​ac+b​​.

34+3.3−1×2+12\frac{3}{4}+3.3-\frac{1\times 2+1}{2}​4​​3​​+3.3−​2​​1×2+1​​

2

Simplify 1×21\times 21×2 to 222.

34+3.3−2+12\frac{3}{4}+3.3-\frac{2+1}{2}​4​​3​​+3.3−​2​​2+1​​

3

Simplify 2+12+12+1 to 333.

34+3.3−32\frac{3}{4}+3.3-\frac{3}{2}​4​​3​​+3.3−​2​​3​​

4

Simplify.

5.12\frac{5.1}{2}​2​​5.1​​

5

Simplify.

2.552.552.55

6 0
2 years ago
What is the least common multiple of 10, 20, and 14?
lyudmila [28]

Answer:

The least common multiple would be 140.

Step-by-step explanation:

The least common multiple is known to be a multiple that is the lowest value that satisfies being a multiple with the other factors given.

The least common multiple was 140 as it was the lowest value that satisfied being a multiple of 14, 10, AND, 20,

14 * 10 = 140

20 * 7 = 140

10 * 14 = 140

7 0
2 years ago
REALLY APPRECIATE YOUR HELP<br><br>Given log x = 3 and log y = 2, prove that x^2 -7xy =3000y​​
anyanavicka [17]

Answer:

if \:  log(x )  = 3 \\  log_{10}(x)  = 3 \\   {10}^{3}  = x \\ therfore \to \:  \boxed{x =  {10}^{3} } \\ \\  if \:  log(y )  = 2 \\  log_{10}(y)  = 2 \\   {10}^{2}  = y \\ therfore \to \:  \boxed{y=  {10}^{2} }

Step-by-step explanation:

x^2 -7xy =3000y \: then \to \\ x^2 =3000y + 7xy \\ {(10 ^{3} )}^{2}  = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{3} \times  {10}^{2})  \\   {10}^{6}   = 3000(10)^{2}    + 7( {10}^{5} )   \\  {10}^{6}  = 300000 + 700000 \\   \boxed{{10}^{6}  = 1000000} \\ hence \: the \: equation \to \: x^2 -7xy =3000y \\ \boxed{ is \: corret}

♨Rage♨

3 0
3 years ago
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