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kow [346]
3 years ago
13

Plzz helppp i don't understand​

Mathematics
2 answers:
vivado [14]3 years ago
6 0

Answer:

40

Step-by-step explanation:

The denominators are 4, 5, and 8.

Write the prime factorizations:

4 = 2²

5 = 5

8 = 2³

To find the least common denominator, multiply the prime numbers with the highest exponents.

2³ × 5 = 40

DedPeter [7]3 years ago
4 0

Answer:

LCD=40

EXPLANATION= To find the least common denominator first convert all integers and mixed numbers (mixed fractions) into fractions. Then find the lowest common multiple (LCM) of the denominators.

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What is the solution to the equation 1^6 x = 2 ?
Dvinal [7]

1^6 is just 1 so 1x=2, you can just take away the one because it is a given that if there is an x there is a 1, so the answer is x=2

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3 years ago
Can anyone help find the area pls ty
AlexFokin [52]

Answer:

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Step-by-step explanation:

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1 year ago
Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e
DENIUS [597]
Hello,

Reminders:
$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$&#10;&#10;&#10;
$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$&#10;&#10;
$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $&#10;

n=6\\&#10;x_{0}=0\\&#10;x_{n}=3\\&#10;\Delta= \dfrac{x_n-x_0}{n}=0.5\\&#10;&#10;
x_{i} =0+\Delta*i= \frac{i}{2}

$ \sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\  \dfrac{i^3/8-6i}{2} $
$= \dfrac{1}{2}\sum_{i=1}^{6}  (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575


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8 0
3 years ago
Read 2 more answers
22% of the customers visiting the suit department of a certain store will purchase a suit, 30% will purchase a shirt and 28% wil
Ulleksa [173]

Answer:

If there are 1000 customers in the store one week, how many will purchase exactly one of these items

1000 CUSTOMERS*28%=280

Step-by-step explanation:

A The event that a persons buys a suit  

B The event that a person buys a shirt  

C The event that a person buys a tie  

 

P(A)=  22%

P(B)=  30%

P(C)=  28%

P(AB)= 11%

P(AC)= 14%

P(BC)= 10%

P(ABC)= 6%

A u B u C Is the event that any item is bougth

AC u AC u BC Is the event that any two events occured

So the wanted probability is

P[(A u B u C )(AB u AC u BC)^c

P[(A u B u C )=P(AB)+ P(BC)+P(BC)

P[(A u B u C ) =0.22+0.30+0.28-0.11-0.14.-0.10+0.06

                      =0,51

0,51=+0,23+P[(A u B u C )(AB u AC u BC)^c

        =0,28

1000 CUSTOMERS*28%=280

6 0
3 years ago
E
xz_007 [3.2K]

Answer:

1) n = 84

2) n = 78

3) n = 24

4) n = 16

5) n = 35

Step-by-step explanation:

To solve each proportion, we apply cross multiplication.

Question 1:

\frac{5}{12} = \frac{35}{n}

5n = 35*12

Simplifying both sides by 5

n = 7*12 = 84

Question 2:

\frac{n}{52} = \frac{180}{120}

120n = 52*180

Simplifying both sides by 20

6n = 52*9

Simplifying by 3

2n = 52*3

Simplifying by 2

n = 26*3 = 78

Question 3:

\frac{18}{n} = \frac{21}{28}

21n = 18*28

Simplifying both sides by 7

3n = 18*4

Simplifying both sides by 3

n = 6*4 = 24

Question 4:

\frac{n}{4} = \frac{24}{6}

\frac{n}{4} = 4

n = 16

Question 5:

\frac{10}{16} = \frac{n}{56}

16n = 56*10

Simplifying by 2, both sides

8n = 56*5

Simplifying by 8, both sides

n = 7*5 = 35

4 0
3 years ago
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