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3 years ago

Find the first five terms of the sequence below a1=3 An=an-1+6

Mathematics

1 answer:

mihalych1998 [28]3 years ago

4 0

The first dove terms are:3,9,12,15,18

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Last year, a car dealership sold 144 new cars and 108 used cars. Since then, the number of new cars sold is increasing by 8 cars

-BARSIC- [3]

The answer is “B”
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6 0

3 years ago

Choose the equation that represents a line that passes through points (−1, 2) and (3, 1).

3241004551 [841]

You did not provide us with equations to select.

Find the slope m.

m = (1 - 2)/(3 - (-1))

m = -1/(3 + 1)

m = -1/4

Use the slope and one of the points and plug into the point-slope formula.

y - 1 = (-1/4)(x - 3)

Isolate y.

y - 1 = (-1/4)x + (3/4)

y = (-1/4)x + (3/4) + 1

y = (-1/4)x + (7/4)

Did you follow?

5 0

3 years ago

Read 2 more answers

Can someone help me please I need the mode, median, range and the mean.?

Neko [114]

Answer:

First the mode. Since 5 popped up the most, 5 is the mode.

Next is the median. I crossed 1 dot from each side until it shows the last dot, and 5 was the last one.

After that the range. 9-2=7

Finally the worst, the mean... 2+2+3+3+3+4+5+5+5+5+5+6+6+6+8+9+9+9+9

=104/19=5.47

SO, Mode=5 Median=5 Range=7, and the mean is 5.47 (rounded nearest hundred)

7 0

3 years ago

Find the value of x for which 2x ^(1/ 2) = 32.

Mrac [35]

Answer:

The value of x will be 8

Step-by-step explanation:

We have given that $2\sqrt{x}=32$

We have to find the value of x

As $2\sqrt{x}=32$

For finding the value of x we have to square both side

On squaring both side

We done squaring both side for easy simplification

$4x=32$

So x = 8

So the value of x will be 8

So answer will be 8

5 0

3 years ago

The roots of a quadratic equation ax2+bx+c=0 are 1+i 5 and 1−i 5 . Find possible values of a, b and c.

Anarel [89]

Answer:

Step-by-step explanation:

If the roots are 1 + 5i and 1 - 5i, then you need the factors that result from those roots. They are (x - 1 + 5i) and (x - 1 - 5i). Now what you do with those is FOIL them out. Doing that gives you the following:

$x^2-x+5ix-x+1-5i-5ix+5i-25i^2$ (what a mess, huh?)

The good thing is that several of those terms cancel each other out. +5ix cancels out the -5ix; -5i cancels out the 5i; and the 2 -x terms combine to -2x. That leaves you with:

$x^2-2x-25i^2$

Obviously you're in the section in math that deals with complex (imaginary) numbers so you should know that i-squared is equal to -1. Making that replacement:

$x^2-2x+25$

a = 1, b = -2, c = 25

6 0

3 years ago

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