This is the concept of linear proportionality, we are required to calculate the actual length between two buildings which have a distance of 1.7 cm when drawn to scale of 1 cm: 2.5 km. This can be calculated as follows;
actual distance= (distance on the map)*(scale factor)
actual distance=1.7*2.5=4.25 km
The answer is 4.25 km
Step-by-step explanation:
The ratio of the perimeters = the scale
P₂ / P₁ = 6 / 4 = 3 / 2
The ratio of the areas = the square of the scale
A₂ / A₁ = (6 / 4)² = (3 / 2)² = 9 / 4
Same for the triangles:
P₂ / P₁ = 6 / 3 = 2
A₂ / A₁ = (6 / 3)² = (2)² = 4
Answer:
K'O' is parallel to KO and its length = 5 * length of KO.
Step-by-step explanation:
The image is missing but I found a very similar problem on Brainly: brainly.com/question/7154536 I think the image is comparable even though it said KL instead of KO.
Assuming that is the case, because the larger figure was dilated using a scale factor of 5, K'O' is parallel to KO and its length = 5 * length of KO.
The answer is A because when the two lines are on the outside of a term like that it means that what ever is inside is the opposite of the original number
For ex. | 4 | < 4
The 1st number will be a negative so it makes the statement true
Answer:
1, 2 and 5 all know each other.
Step-by-step explanation:
I will denote the people by numbers: 1 2 3 4 5 6 7 8 9
The following information is given in the question.
1 knows two others
2 knows five others
3 knows five others
4 knows six others
5 knows six others
Let's assume the worst case: They all know different persons, so it is difficult to find three people who all know each other.
1 knows 2 and 5
2 knows 1 3 4 5 6
3 knows 9 8 7 6 2
By now, 2, 5 and 6 are known to two people, and others are known to just one person.
4 knows 9 8 7 6 5 3
5 knows 1 2 4 7 8 9
As a result 1, 2 and 5 all know each other.
1 knows 2 and 5
2 knows 1 and 5
5 knows 1 and 2
The reason for this is that there are three groups:
1, (2,3) and (4,5)
As much as we try to separate the people that they know there are nine different persons and at least three of them will be spread to these groups in common.
