Answer:
Option D, 32
Step-by-step explanation:
<u>Step 1: Identify the equation</u>
6y = 192
<u>Step 2: Solve for y by dividing both sides by 6</u>
6y / 6 = 192 / 6
y = 32
Answer: Option D, 32
Answer:
10 and 15
Step-by-step explanation:
Let 'x' and 'y' are the numbers we need to find.
x + y = 25 (two numbers whose sum is 25)
(1/x) + (1/y) = 1/6 (the sum of whose reciprocals is 1/6)
The solutions of the this system of equations are the numbers we need to find.
x = 25 - y
1/(25 - y) + 1/y = 1/6 multiply both sides by 6(25-y)y
6y + 6(25-y) = (25-y)y
6y + 150 - 6y = 25y - (y^2)
y^2 - 25y + 150 = 0 quadratic equation has 2 solutions
y1 = 15
y2 = 10
Thus we have
:
First solution: for y = 15, x = 25 - 15 = 10
Second solution: for y = 10, x = 25 - 10 = 15
The first and the second solution are in fact the same one solution we are looking for: the two numbers are 10 and 15 (since the combination 10 and 15 is the same as 15 and 10).
1/64 & 16
hope that helped :)
Answer:
Step-by-step explanation:
(2x^2+6x-8)(x+3)
2x^3+6x^2+6x^2+18x-8x+18
2x^3+12x^2+10x+18
