The number of ways for which she could pick four colours if green must be one of them is; 10 ways.
<h3>How many ways can she picks four colours if green must be there?</h3>
It follows from the task that there are 6 colours in total that she could pick from.
Hence, since she needs four colours with green being one of them, it follows that she only has 3 colours to pick from 5.
Hence, the numbers of possible combinations is; 5C3 = 10 ways.
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Answer:NIce
Step-by-step explanation:
Answer:
11x^2-8x-14
Step-by-step explanation:
(2x^2- 8x– 6)+(9x^2-8) = 11x^2-8x-14
Answer:
Final result :
x + 2
—————
x - 1
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 7 • 3 = 21
Step-2 : Find two factors of 21 whose sum equals the coefficient of the middle term, which is -10 .
-21 + -1 = -22
-7 + -3 = -10 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -7 and -3
7x2 - 7x - 3x - 3
Step-4 : Add up the first 2 terms, pulling out like factors :
7x • (x-1)
Add up the last 2 terms, pulling out common factors :
3 • (x-1)
Step-5 : Add up the four terms of step 4 :
(7x-3) • (x-1)
Which is the desired factorization
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The cost of one slice of mushroom pizza is $2.00 dollars. This is solved by subtracting the equations:
X = cheese pizza
Y = mushroom pizza
(3X + 4Y = 12.50)
- (3X + 2Y = 8.50)
______________
2Y = 4.00
Y=2 or a slice of mushroom pizza is $2.00.
