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3 years ago

Find each sum.Simplify if possible

Mathematics

2 answers:

Alex Ar [27]3 years ago

8 0

Number 2 is 7 9/8 but its an improper fraction so you'll have to reduce that since im having trouble doing that.

Number 5 is 9 11/12

Hope this helps!

Dmitrij [34]3 years ago

6 0

2) 6 3/4 is = to 6 6/8 1 3/8 + 6 6/8= 8 1/8 The answer is 8 1/3 5) 3 1/4 ×3=3 3/12 6 2/3 ×4=6 8/12 3 3/12+ 6 8/12= 9 11/12 The answer is 9 11/12

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What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

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3 years ago

Read 2 more answers

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sertanlavr [38]

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Have a great day, and sorry if i got it wrong. <3

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Answer:

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telo118 [61]

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