Answer:
the answer is D
Step-by-step explanation:
Here we have a case of the least common multipl(lcm) of 6 and 20.
Prime numbers 2,3,5,7,11,13,17,19... (natural numbers greater than 1 that has no positive divisors other than 1 and itself) .
lcm(6,20)= 6 20 | 2
3 10 | 3
1 10 | 2
5 | 5
1
2*3*2*5=60 The first one to get both calendar and the animal toy will be 60th.
Explenation: First we look for the smallest prime number with wich 6 and 20 can be devided by. That is 2. Next is 3. Since 10 is not divisible by 3, we only copy it. Under the 6 we got 1, wich is our goal. Now we continue to devide 10 by prime numbers till we also get 1. We now multiple all divisors and we get the least common multiple.
Answer:
y1= 0, y2= 5/3
Step-by-step explanation:
Remove the parentheses and multiply
then cancel the equal terms
collect the lie terms
move the variables to one side
divide both sides by two
split into possible cases
then solve the equation to get
y= 0 and
y= 5/3
Answer:
16 3/10
Step-by-step explanation:
Think about what fraction become .3 when put into a calculator
that's a 3 in the tenths place in the decimal system so the fraction would be 3/10. Then finally add on the 16
*an aside if this is wrong it it is possible that they have rounded 1/3 to one decimal place. (1/3 is usually .33333 repeating)
