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Crank
4 years ago
6

Find the slope of the line that passes through (2, 12) and (5, 10).

Mathematics
2 answers:
Katarina [22]4 years ago
7 0

Answer:

-2/3

Step-by-step explanation:

m = (y2-y1)/(x2-x1)

(10-12)/(5-2) = -2/3

Darina [25.2K]4 years ago
6 0

The right answer is -2/3

please see the attached picture for full solution

Hope it helps..

Good luck on your assignment..

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In how many different orders can you line up 8 cards on a table
Fynjy0 [20]
You can line up 8 cards 64 different ways. 

8 * 8 = 64
3 0
3 years ago
Read 2 more answers
For what value of x does (x + 3)^2-5=0
ArbitrLikvidat [17]

Answer:

x = -3±sqrt( 5)

Step-by-step explanation:

(x + 3)^2-5=0

Add 5 to each side

(x + 3)^2-5+5=0+5

(x + 3)^2 = 5

Take the square root of each side

sqrt((x + 3)^2 )=±sqrt( 5)

x+3 = ±sqrt( 5)

Subtract 3 from each side

x+3-3 = -3±sqrt( 5)

x = -3±sqrt( 5)

7 0
4 years ago
30 POINTS! PLEASE HELP
Kryger [21]

Answer:

y = -4x+4

Step-by-step explanation:

Pick two points on the line

(0,4) and (1,0)

We can find the slope

m = (y2-y1)/(x2-x1)

   = (0-4)/(1-0)

   = -4/1 =-4

We know the y intercept is 4

The slope intercept form of the equation is y = mx+b  where m is the slope and b is the y intercept

y = -4x+4

8 0
3 years ago
Read 2 more answers
Which of the binomial is a factor of this trinomial x2-7x-44?
yan [13]
I hope this helps you



x^2-7x-44

x -11



x +4



(x-11)(x+4)
6 0
3 years ago
I don't know how to solve it.
Nataly [62]

Step-by-step explanation:

Take the first derivative

\frac{d}{dx} ( {x}^{3}  - 3x)

3 {x}^{2}  - 3

Set the derivative equal to 0.

3 {x}^{2}  - 3 = 0

3 {x}^{2}  = 3

{x}^{2}  = 1

x = 1

or

x =  - 1

For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).

For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.

Since we are going to Positve to negative slope, we have a local max at x=-1

Plug in -1 for x into the original function

( - 1) {}^{3}  - 3(  - 1) = 2

So the local max is 2 and occurs at x=-1,

For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.

Since we are going to decreasing to increasing, we have minimum at x=1,

Plug in 1 for x into original function

{1}^{3}   - 3(1)

1 - 3 =  - 2

So the local min occurs at -2, at x=1

8 0
2 years ago
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