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3 years ago

What is the quotient of the polynomials shown below?

Mathematics

1 answer:

Zolol [24]3 years ago

5 0

Answer:

Option A is correct.

Step-by-step explanation:

We need to find the quotient of the polynomials

$(6x^3+8x^2+16)\div(2x+4)$

The quotient is: 3x^2-2x+4

The remainder is: 0

The division is shown in the figure attached.

Option A is correct.

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find the centre and radius of the following Cycles 9 x square + 9 y square +27 x + 12 y + 19 equals 0

Citrus2011 [14]

Answer:

Radius: $r =\frac{\sqrt {21}}{6}$

$Center = (-\frac{3}{2}, -\frac{2}{3})$

Step-by-step explanation:

Given

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Solving (a): The radius of the circle

First, we express the equation as:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

So, we have:

$9x^2 + 9y^2 + 27x + 12y + 19 = 0$

Divide through by 9

$x^2 + y^2 + 3x + \frac{12}{9}y + \frac{19}{9} = 0$

Rewrite as:

$x^2 + 3x + y^2+ \frac{12}{9}y =- \frac{19}{9}$

Group the expression into 2

$[x^2 + 3x] + [y^2+ \frac{12}{9}y] =- \frac{19}{9}$

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

Next, we complete the square on each group.

For $[x^2 + 3x]$

1: Divide the $coefficient\ of\ x\ by\ 2$

2: Take the $square\ of\ the\ division$

3: Add this $square\ to\ both\ sides\ of\ the\ equation.$

So, we have:

$[x^2 + 3x] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}$

$[x^2 + 3x + (\frac{3}{2})^2] + [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Factorize

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y] =- \frac{19}{9}+ (\frac{3}{2})^2$

Apply the same to y

$[x + \frac{3}{2}]^2+ [y^2+ \frac{4}{3}y +(\frac{4}{6})^2 ] =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ (\frac{3}{2})^2 +(\frac{4}{6})^2$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =- \frac{19}{9}+ \frac{9}{4} +\frac{16}{36}$

Add the fractions

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{-19 * 4 + 9 * 9 + 16 * 1}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{21}{36}$

$[x + \frac{3}{2}]^2+ [y +\frac{4}{6}]^2 =\frac{7}{12}$

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

By comparison:

$r^2 =\frac{7}{12}$

Take square roots of both sides

$r =\sqrt{\frac{7}{12}}$

Split

$r =\frac{\sqrt 7}{\sqrt 12}$

Rationalize

$r =\frac{\sqrt 7*\sqrt 12}{\sqrt 12*\sqrt 12}$

$r =\frac{\sqrt {84}}{12}$

$r =\frac{\sqrt {4*21}}{12}$

$r =\frac{2\sqrt {21}}{12}$

$r =\frac{\sqrt {21}}{6}$

Solving (b): The center

Recall that:

$(x - h)^2 + (y - k)^2 = r^2$

Where

$r = radius$

$(h,k) =center$

From:

$[x + \frac{3}{2}]^2+ [y +\frac{2}{3}]^2 =\frac{7}{12}$

$-h = \frac{3}{2}$ and $-k = \frac{2}{3}$

Solve for h and k

$h = -\frac{3}{2}$ and $k = -\frac{2}{3}$

Hence, the center is:

$Center = (-\frac{3}{2}, -\frac{2}{3})$

6 0

2 years ago

For every watch that Sarah sells, she earns $4. She gets an additional bonus of $50 for every 25 watches she sells. Last month,

kotegsom [21]

Answer:

Step-by-step explanation:

25 watches equals a $50 bonus + 25 * 4

25*4=100

100+50=150

150 can go into 506 three times with a remainder of 56.

since it fits three times that is 75 watches

now divided the remainder by 4 and add this to 75.

56/4=14

75+14=89

89 watches

4 0

3 years ago

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PLEASEEEE HELPPP MEEE WITHHH THISS QUESTIONN PLEASEEE!!!!<br> I NEED A GREAT EXPLANATION PLEASEE!!!!

ipn [44]

The diagonal of a rhombus divides it into two congruent isosceles triangles.

So ∠CBD ≅ ∠CDB

∠CBD + ∠CDB + 68 = 180

2∠CBD = 180 - 68 = 112

∠CBD = 56

We also have

∠BDE + ∠E + ∠DBE = 180

∠DBE = 180 - 73 - 36 = 71

∠EBC = ∠EBD - ∠CBD = 71 - 56 = 15

Answer: ∠EBC = 15 degrees

4 0

3 years ago

i forgot how to find equivalent fractions. i know that the bottom would be times by 3 to get 18 but if you times 3 by 3 it would

tester [92]

Set up a proportion. take 3/6 = 20/x
Cross multiply 3 * x = 6 * 20
Simplify 3x = 120
Divide by 3 x = 40
So the denominator of the bottom fraction is 40

6 0

3 years ago

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Look at the picture below and answer correctly so i can mark you as brainliest

aleksandrvk [35]

Answer:

The domain is 0, 2 ,5

Step-by-step explanstion

The domain for a set of points are the x corridinates.

Now give me brainliest

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2 years ago

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