Question

Identify the graph of 4x^2+5y^2=20 for T(5,-6) and write an equation of the translated or rotated graph in general form. (picture provided)

Answer 1

Answer:

b. ellipse; $4x^2+5y^2-40x+60y+260=0$

Step-by-step explanation:

The graph of $4x^2+5y^2=20$ an ellipse because the coefficients of the quadratic terms are not the same.

This ellipse is centered at the origin. If this ellipse is translated  so that its center is now at $(5,-6)$.

Then the translated ellipse will now have equation.

$4(x-5)^2+5(y+6)^2=20$

We expand to get;

$4(x^2-10x+25)+5(y^2+12y+36)=20$

$4x^2-40x+100+5y^2+60y+180=20$

$4x^2+5y^2-40x+60y+100+180-20=0$

$4x^2+5y^2-40x+60y+260=0$

Answer 2

Answer:

B

Step-by-step explanation:

just took it on edge and it was right :)