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stellarik [79]
3 years ago
10

Given the points A(-1,-3) and B(5,2). A. Write the equation of the straight line AB. Another line MN is parallel to AB and passe

s through the point (6,-2). B. Write the equation of the straight line MN
Mathematics
1 answer:
Alexus [3.1K]3 years ago
8 0
<u>Find slope of AB where A = (-1,-3) and B = (5,2):</u>

\text {Slope = }  \dfrac{Y_2-Y_1}{X_2-X_1}

\text {Slope = }  \dfrac{2+3}{5+1} =  \dfrac{5}{6}

<u>Write equation with the slope found:</u>

y = mx + b

y =  \dfrac{5}{6} x + b

<u>Find y-intercept:</u>

y = \dfrac{5}{6} x + b

2 = \dfrac{5}{6} (5) + b

2 = \dfrac{25}{6} + b

b = 2 - \dfrac{25}{6}

b = -\dfrac{13}{6}

<u>Form the equation:</u>

y = \dfrac{5}{6} x  - \dfrac{13}{6}

\boxed {\boxed {\bf \text {Answer: Line AB : }y = \dfrac{5}{6} x - \dfrac{13}{6}}}

<u>
Find Slope of Line  MN where MN is parallel to AB:</u>

\text {Slope of MN  = Slope of AB = }  \dfrac{5}{6}

<u>Write equation with the slope found:</u>

y = mx + b

y = \dfrac{5}{6} x + b

<u>Find y-intercept given that the line passed through (6, -2):</u>

y = \dfrac{5}{6} x + b

-2 = \dfrac{5}{6} (6) + b

-2 =5 + b

b = -2 - 5

b = -7

&#10;\boxed {\boxed {\bf \text {Answer: Line MN } : y = \dfrac{5}{6} x -7 }}

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