A =7
7^2*3.14*7 sorry I did the equation wrong at first
The true statement is the circle has the radius equal to 7.
<h3>What is Equation of circle?</h3>
The general equation for a circle is (x-h)² + (y-k)² = r², where ( h, k ) is the center and r is the radius.
As, standard form of equation of circle is
(x-h)² + (y-k)² = r²
At origin, equation of circle will be
(0-h)² + (0-k)² = r²
r² = x² + y²
Now, The line intersects the circle at (0,7)
r² = 0² + 7²
r² =49
r=7.
Hence, the circle has the radius equal to 7.
Learn more about this concept here:
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hello :<span>
<span>an equation of the circle Center at the
A(a,b) and ridus : r is :
(x-a)² +(y-b)² = r²
in this exercice : a =0 and b = 0 (Center at the origin)
r = OP....p(-8,3)
r² = (OP)²
r² = (-8-0)² +(3-0)² = 64+9=73
an equation of the circle that satisfies the stated conditions.
Center at the origin, passing through P(-8, 3) is : x² +y² = 73</span></span>
A. Terms
b. 9
64 to 49 is -15, 49 to 36 is -13, 36 to 25 is -11, 25 to 16 is -9, so the next number is 16-7=9
