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adell [148]
3 years ago
10

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

!!!!!!!!!!!!!!!Savannah recently bought a 65 inch flat screen television. Television dimensions refer to the diagonal size of the screen. Savannah knows that the television is 56.7 inches wide. The height of the television is approximately inches.
Mathematics
2 answers:
aliya0001 [1]3 years ago
6 0

Answer:

Approximately 32 in

Step-by-step explanation:

This is a Pythagorean Theorem problem: we have the hypotenuse (diagonal size) and the leg (width). Now solve for the height.

a^2 + b^2 = c^2

56.7^2 + b^2 = 65^2

b^2 = 1010.11

<u>b = 31.78 in ≈ 32 in</u>

goldfiish [28.3K]3 years ago
4 0

Answer:

. The height of the television is approximately  32 inches or 2 1/3 feet

Step-by-step explanation:

Use Pythagoras' Theorem that says that in a right triangle the square of the hypotenuse is equal to the sum of the squares of the other two sides.

a²+b² = c²

diagonal =c = 65

56.7 could be a or b so

56.7²+b² = 65²

3124.89+ b² = 4225

b² = 4225 - 3124.89

b² = 1010.11 take a √ to find b

b = 31.78

round to 32 inches

1 foot =12 inches

32/12 = 8/3 = 2 1/3

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b) 0.017 = 1.7% probability that a disk has at least two missing pulses

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Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

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&#10;e = 2.71828 is the Euler number

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Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Poisson mean:

\mu = 0.2

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

P(X \geq 2) = 1 - P(X < 2)

In which

P(X < 2) = P(X = 0) + P(X = 1)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}&#10;

P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819

P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164&#10;

P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so p = 0.181

We want to find P(X = 0).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671

0.671 = 67.1% probability that neither contains a missing pulse

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