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3 years ago

What is the solution of the system?

1 answer:

6 0

Equation 1 - equation 2: (y-y)=(10x-2)-(-7x+3)
17x-5=0
x=5/17
so answer A is correct.
double check: 10(5/17)-2=50/17-34/17=16/17. Yes.

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PLEASE HELP ASAP! THANK YOU

Dafna1 [17]

Answer:

39 m.

Step-by-step explanation:

The area of a triangle is calculated by the expression given as:

Area = bh/2

where b is the base and h is the height.

We calculate as follows:

270 = b (15) / 2

b = 36

hypotenuse = sqrt ( 15^2 + 36^2 ) = 39

4 0

3 years ago

a leak is slowly draining water from a pool containing 324 gallons of water. How much water is remaining after 8 hours if it lea

sergey [27]

268 gallons are remaining. The equation would be y=324-7x, with x being 8. 7(8) is 56, and then you take away 56 from 324, which then gives you 268 gallons remaining

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3 years ago

Consider the following hypothesis test:

Gnom [1K]

Answer:

a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.

b. z=1.24. No, it can not be concluded that the population mean is greater than 50.

c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.

Step-by-step explanation:

We have a hypothesis test for the mean, with the hypothesis:

$H_0: \mu\leq50\\\\H_a:\mu> 50$

The sample size is n=55 and the population standard deviation is 6.

The significance level is 0.05.

We can calculate the standard error as:

$\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809$

For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.

a. If the sample mean is M=52.5, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

b. If the sample mean is M=51, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24$

The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.

c. If the sample mean is M=51.8, the test statistic is:

$z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22$

The null hypothesis is rejected, as z>zc and falls in the rejection region.

8 0

3 years ago

A noted psychic was tested for extrasensory perception. The psychic was presented with 2 0 0 cards face down and asked to determ

Natasha2012 [34]

Answer:

C. P- value < 0.04 0.05

Step-by-step explanation:

hello,

we were given the sample size, n = 200

also the probability that the psychic correctly identifies the symbol on the 200 card is

$p=\frac{50}{200}= 0.25$

using the large sample Z- statistic, we have

$Z=\frac{p- 0.20}{\sqrt{0.2(1-0.2)/200} }$

= $\frac{0.25-0.20}{\sqrt{0.16/200}}$

= 1.7678

thus the P - value for the hypothesis test is P(Z > 1.7678) = 0.039.

from the above, we conclude that the P- value < 0.04, 0.05

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3 years ago

Unit 5 Test

8090 [49]

Answer:

is 23,13 usjebiddje

Step-by-step explanation:

jsjsjebjeh3he

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3 years ago