Use the standard normal table to find the z-score that corresponds to the given percentile. if the area is not in the table, u
se the entry closest to the area. if the area is halfway between two entries, use the z-score halfway between the corresponding z-scores. if convenient, use technology to find the z-score. upper p 8p8
1 answer:
You need to look for the area to the left of the z-score from the table.
i found a z-score of.84 yielded .7995 area to the left of that z-score and i found a z-score of .85 yielded .8024 area to the left of that z-score.
0.7995 is much closer to 0.80 than 0.8024, so the z-score chosen as the solution is a z-score of .84.
the z-score of .84 is an addition of 0.8 in column 1 with .04 in column 7
it's the intersection of the area in the row of .8 with the column of .04.
this is shown in the following picture.
i found a z-score of.84 yielded .7995 area to the left of that z-score and i found a z-score of .85 yielded .8024 area to the left of that z-score.
0.7995 is much closer to 0.80 than 0.8024, so the z-score chosen as the solution is a z-score of .84.
the z-score of .84 is an addition of 0.8 in column 1 with .04 in column 7
it's the intersection of the area in the row of .8 with the column of .04.
this is shown in the following picture.
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