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pishuonlain [190]
3 years ago
13

What is the value of the 2 in 5,632

Mathematics
2 answers:
Luda [366]3 years ago
8 0
2 ones
Since the value is in the one place therefor it is 2 ones
NISA [10]3 years ago
4 0

Answer:

<u>The value would be </u><u>2 ones</u><u>.</u>

Step-by-step explanation:

Since the 2 is in the ones place, and the 2 means...well 2, it shows that there a 2 ones.

<em>Hope that helped!!</em>

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Filomena applies the commutative property to the product. (7/15)⋅(−11)⋅(30) Which expression illustrates the commutative propert
dedylja [7]

  • The commutative property is a number property where the answer obtained is the same no matter the position of the numbers you are multiplying together.

  • Commutative property of multiplication is expressed as:

        a x b = b x a

        a x b x c = a x c x b = b x c x a

  • Note: " . " in the question also means "x" (multiplication)

  • Applying commutative property to the question:

(7/15)⋅(−11)⋅(30)

(7/15) ⋅ (−11) ⋅ (30) = (7/15) . (30) . (11)

The values interchanged are: 11 and 30. The result of the multiplication remains unchanged.

Option A  is the correct answer.

To learn more, visit the link:

brainly.com/question/24733555

8 0
2 years ago
Read 2 more answers
Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,
sweet [91]

Answer:

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

f'' = x - \frac{3}{2}

f' = \int {\left(x-\frac{3}{2}\right) } \, dx

f' = \int {x} \, dx -\frac{3}{2}\int \, dx

f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C, where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative (f'(4) = 1):

1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C

C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)

C = -1

The first derivative is y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1, and the particular solution is found by integrating one more time and using the initial condition (f(0) = 0):

y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1  \right)} \, dx

y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx

y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C

C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0

C = 0

Hence, the particular solution of the differential equation is y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x.

5 0
3 years ago
The line with slope -1/4 and passing through (1,2)
Deffense [45]

Answer:

the correct answer is Y=-x-3

8 0
3 years ago
How to model using base 10 blocks to multiply 4x16
uysha [10]

Answer:

Step-by-step explanation:

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3 0
3 years ago
BC = 36; D = 15. What is the value of BD - AC.<br> B<br> A<br> BD - AC =
Snezhnost [94]

Answer:

BD - AC = 0

Step-by-step explanation:

Given that:

BC = 36 , CD = 15 and BD = x

As these are forming right angled triangle,

Using Pythagorean theorem,

(BD)^2+(CD)^2=x^2\\(36)^2+(15)^2 = x^2\\1296 + 225 = x^2\\1521 = x^2\\

Taking square root on both sides

\sqrt{x^2}=\sqrt{1521}\\x=39

As the given shape is rectangular, the sides parallel to each other will have same values.

AB = 15 , AD = 36 and AC = x

(15)^2+(36)^2 = x^2 \\225 + 1296 = x^2 \\1521 = x^2 \\x = 39

Now,

BD - AC = 39 - 39 = 0

Hence,

BD - AC = 0

5 0
3 years ago
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