40 - 23<br> 4 + 3(22)<br> evaluate the expression

Pls help with this one I will give you brainliest thank you!

finlep [7]

Answer:

$\boxed{Volume \: of \: right \: rectangular \: prism = 790 \: {meter}^{3}}$

Explanation:

Volume of right rectangular prism is same as volume of cuboid

Length = 22.9 meters

Width = 7.5 meters

Height = 4.6 meters

Volume of right rectangular prism = Length × Width × Height

= 22.9 × 7.5 × 4.6

= 22.9 × 34.5

= 790.05 meter³

= 790 meter³

8 0

3 years ago

What 5x23p9x2 and what is the common number?

loris [4]

Hi There! :)

<span>What 5x23p9x2 and what is the common number?

5</span>×23=115
<span>115</span>×9=1035
<span>1035</span>×2=2070
<span>
Therefore 2070 is the answer
</span>

5 0

4 years ago

What is the approximate area of a circle with a radius of 4 feet? Use 3.14

Eva8 [605]

Answer:

≈ 50 ft²

Step-by-step explanation:

<u>Area of circle:</u>

A = πr²

<u>Given:</u>

r = 4 ft, π = 3.14

A= 3.14 * 4² = 50.24 ≈ 50 ft²

8 0

3 years ago

Real world situation for 834+14s>978-10s

liraira [26]

834+14s=848>978-10s=968

a real life situation for that could be like how many apples 848apples/968total

6 0

3 years ago

Below are survival times (in days) of 13 guinea pigs that were injected with a bacterial infection in a medical study:

tresset_1 [31]

Outliers are data that are relatively far from other data elements.

The dataset has an outlier and the outlier is 120

The dataset is given as:

91 83 84 79 91 93 95 97 97 120 101 105 98

Sort the dataset in ascending order

79 83 84 91 91 93 95 97 97 98 101 105 120

<h3>The lower quartile (Q1)</h3>

The Q1 is then calculated as:

$Q1 = \frac{N +1}{4}th$

So, we have:

$Q1 = \frac{13 +1}{4}th$

$Q1 = \frac{14}{4}th$

$Q1 = 3.5th$

This is the average of the 3rd and the 4th element

$Q1 = \frac{1}{2} \times (84 + 91)$

$Q1 = 87.5$

<h3>The upper quartile (Q3)</h3>

The Q3 is then calculated as:

$Q3 = 3 \times \frac{N +1}{4}th$

So, we have:

$Q3 = 3 \times \frac{13 +1}{4}th$

$Q3 = 3 \times 3.5th$

$Q3 = 10.5th$

This is the average of the 10th and the 11th element.

$Q_3 =\frac12 \times (98 + 101)$

$Q_3 =99.5$

<h3>The interquartile range (IQR)</h3>

The IQR is then calculated as:

$IQR = Q_3 -Q_1$

$IQR = 99.5 - 87.5$

$IQR = 12$

Also, we have:

$IQR(1.5) = 12 \times 1.5$

$IQR(1.5) = 18$

<h3>The outlier range</h3>

The lower and the upper outlier range are calculated as follows:

$Lower = Q_1 - IQR(1.5)$

$Lower = 87.5- 18$

$Lower = 69.5$

$Upper = Q_3 + IQR(1.5)$

$Upper = 99.5 + 18$

$Upper = 117.5$

120 is greater than 117.5.

Hence, the dataset has an outlier and the outlier is 120

40 - 23 4 + 3(22) evaluate the expression