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MAXImum [283]
3 years ago
6

JM is the perpendicular bisector of LK.

Mathematics
1 answer:
liq [111]3 years ago
6 0

Answer:

jn=ln nk=nm

Step-by-step explanation:

because

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(a(1) = 5/3<br> (a(n) = a(n − 1).(-9)<br> What is the 3rd term in the sequence?
nataly862011 [7]

Answer:-30

Step-by-step explanation:

Third term=a3

an=a(n-1) x (-9)

a3=5/3 x (3-1) x (-9)

a3=5/3 x 2 x -9

a3=(5x2x-9)/3

a3=-90/3

a3=-30

5 0
3 years ago
The sum of two consecutive odd integers is 28. What are the integers?
Fantom [35]
The correct option is B): "<span>Let x = 1st integer. Let x + 2 = 2nd integer.</span><span>"
Given that "The sum of two consecutive odd integers is 28."
 
Now the difference between two odd numbers is 2. So this means that one odd number has to be greater than the other by 2.

Let the smaller number be 'X' therefore the bigger number will be 'x+2' thus x + (x+2) = 28
 
therefore, x + x + 2 = 28 now we subtract "2" from both the sides
therefore, 2x = 26 now dividing throughout by 2 we get:

x = 13 therefore, x + 2 = 13+2
                                    = 15
 
therefore, the numbers are 13 AND 15</span>
4 0
3 years ago
in a game involving a pair of fair dice a player rolls the dice until he gets a sum of 7 let z equal the number of rolls it take
Anarel [89]

Answer:

z = 36 rolls , probability for getting 7 = 1/6

Step-by-step explanation:

A die has 6 possible outcomes, which sums to 36 for two dice for every value on both dice.

The outcomes for rolling both dice for 36 times gives 6 possible outcomes summing to 7, that is, (1, 6), (2, 5), (3, 4), (4, 3), (5, 2), and (6, 1).

There the probability of getting a sum dice of 7 is:

= 6 / 36 = 1/6

8 0
3 years ago
List the first 10 multiples for each number 3,4,7
notka56 [123]

Answer:

Step-by-step explanation:

3- 3, 6, 9, 12, 15, 18, 21, 24, 27, 30

4- 4, 8, 12, 16, 20, 24, 28, 32, 36, 40

7- 7, 14, 21, 28, 35, 42, 49, 56, 63, 70

HOPE IT HELPED

3 0
3 years ago
Read 2 more answers
There are 92,746 seats available for fans at UGA's Sanford Stadium. Auburn University's Jordan-Hare Stadium has seating for 87,4
Anvisha [2.4K]

Given :

Number of seats at UGA's Sanford Stadium, n_1 = 92,746 .

Number of seats at Auburn University's Jordan-Hare Stadium, n_2=87,451 .

To Find :

How many more seats are there at UGA's stadium.

Solution :

Extra seats at UGA's stadium = seats at UGA's Sanford Stadium - seats at    

                                                     Auburn University's Jordan-Hare Stadium

= 92,746 - 87,451

= 5295

Hence, this is the required solution.

4 0
2 years ago
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