Answer:
C i think
Step-by-step explanation:
Answer:
![\boxed {\boxed {\sf z=2.2}}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Cboxed%20%7B%5Csf%20z%3D2.2%7D%7D)
Step-by-step explanation:
The z-score tells us how many standard deviations a value is away from the mean.
The formula is:
![z=\frac{x- \overline{x}}{s}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7Bx-%20%5Coverline%7Bx%7D%7D%7Bs%7D)
where x is the value,
is the mean, and s is the standard deviation.
We want to find the z-score for the score of an 83, the mean is 72, and the standard deviation is 5.
![x=83 \\\overline {x}= 72 \\s=5](https://tex.z-dn.net/?f=x%3D83%20%5C%5C%5Coverline%20%7Bx%7D%3D%2072%20%5C%5Cs%3D5)
Substitute the values into the formula.
![z=\frac{83-72}{5}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B83-72%7D%7B5%7D)
Solve the numerator.
![z=\frac{11}{5}](https://tex.z-dn.net/?f=z%3D%5Cfrac%7B11%7D%7B5%7D)
Divide.
![z=2.2](https://tex.z-dn.net/?f=z%3D2.2)
The z-score is 2.2, which means the score of 83 is 2.2 standard deviations above the mean.
It is not true because if you add in 0 the equation would be 8-4(0)=4(0)
4x0 = 0
so it would be 8-0=0 which doesn't add up.
you cannot show too much "work"
basically, you remove what is common to all of the factors, and then put brackets, as it will be multiplied back in, remember that when you multiply exponents with the same base, its same as adding them, so subtract to remove...
you can seperate two of the variables , then factor, then subtract the last one from those two, because it cannot be factored out , as in part2 #2
Answer:675
Step-by-step explanation: