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grandymaker [24]
3 years ago
12

X/2 + 1 = 1/4x - 6 solve for x

Mathematics
2 answers:
malfutka [58]3 years ago
6 0

x=-28......................

Natalka [10]3 years ago
5 0
<h3><em>Answer: x = -28</em></h3><h3 /><h3><em>Step-by-step explanation:</em></h3><h3><em>Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : </em></h3><h3><em>x/2+1-(1/4*x-6)=0 </em></h3><h3><em>                     1 </em></h3><h3><em>Simplify      — </em></h3><h3><em>                    4</em></h3><h3 /><h3><em>    x                         1          </em></h3><h3><em>  (— +  1)    -        ((— • x) -  6)  = 0  </em></h3><h3><em>   2                        4         </em></h3><h3 /><h3><em>Subtracting a whole from a fraction </em></h3><h3 /><h3><em>Rewrite the whole as a fraction using  4  as the denominator : </em></h3><h3 /><h3><em>            6             6 • 4 </em></h3><h3><em>    6 =  —  =  ————— </em></h3><h3><em>           1             4   </em></h3><h3><em>Equivalent fraction : The fraction thus generated looks different but has the same value as the whole </em></h3><h3 /><h3><em>Common denominator : The equivalent fraction and the other fraction involved in the calculation share the same denominator</em></h3><h3 /><h3 /><h3><em> Adding up the two equivalent fractions </em></h3><h3><em>Add the two equivalent fractions which now have a common denominator </em></h3><h3 /><h3><em>Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: </em></h3><h3 /><h3><em> x - (6 • 4)                               x - 24 </em></h3><h3><em> ———————————  =  —————— </em></h3><h3><em>      4                                            4   </em></h3><h3><em>   </em></h3><h3 /><h3><em>    x                    (x - 24) </em></h3><h3><em>  (— +  1) -  ————————  = 0  </em></h3><h3><em>   2                 4    </em></h3><h3 /><h3><em>                  x </em></h3><h3><em> Simplify   — </em></h3><h3><em>                  2</em></h3><h3 /><h3 /><h3><em>    x                  (x - 24) </em></h3><h3><em>  (— +  1) -  ————————  = 0  </em></h3><h3><em>   2                 4    </em></h3><h3 /><h3><em>Adding a whole to a fraction </em></h3><h3 /><h3><em>Rewrite the whole as a fraction using  2  as the denominator : </em></h3><h3 /><h3><em>           1            1 • 2 </em></h3><h3><em>    1 =  —  =  ————— </em></h3><h3><em>          1              2  </em></h3><h3 /><h3><em> Adding up the two equivalent fractions </em></h3><h3 /><h3><em>   x + 2              x + 2 </em></h3><h3><em> —————  =  ————— </em></h3><h3><em>    2                    2  </em></h3><h3 /><h3><em>          (x + 2)            (x - 24) </em></h3><h3><em>  ——————— -  ————————  = 0  </em></h3><h3><em>     2                               4    </em></h3><h3 /><h3><em>Find the Least Common Multiple </em></h3><h3 /><h3><em>      The left denominator is :       2  </em></h3><h3 /><h3><em>      The right denominator is :       4  </em></h3><h3 /><h3><em>        Number of times each prime factor </em></h3><h3><em>        appears in the factorization of: </em></h3><h3><em> Prime  </em></h3><h3><em> Factor   Left  </em></h3><h3><em> Denominator   Right  </em></h3><h3><em> Denominator   L.C.M = Max  </em></h3><h3><em> {Left, Right}  </em></h3><h3><em>2 1 2 2 </em></h3><h3><em> Product of all  </em></h3><h3><em> Prime Factors  2 4 4 </em></h3><h3 /><h3><em>      Least Common Multiple: </em></h3><h3><em>      4 </em></h3><h3 /><h3 /><h3><em>Calculate multipliers for the two fractions </em></h3><h3 /><h3 /><h3><em>    Denote the Least Common Multiple by  L.C.M  </em></h3><h3><em>    Denote the Left Multiplier by  Left_M  </em></h3><h3><em>    Denote the Right Multiplier by  Right_M  </em></h3><h3><em>    Denote the Left Deniminator by  L_Deno  </em></h3><h3><em>    Denote the Right Multiplier by  R_ Deno  </em></h3><h3 /><h3><em>   Left_ M = L.C.M / L_ Deno = 2 </em></h3><h3 /><h3><em>   Right_ M = L.C.M / R_Deno = 1</em></h3><h3 /><h3><em> Rewrite the two fractions into equivalent fractions </em></h3><h3 /><h3><em>Two fractions are called equivalent if they have the same numeric value. </em></h3><h3 /><h3><em>For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well. </em></h3><h3 /><h3><em>To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier. </em></h3><h3 /><h3><em>   L. Mult. • L. Num.      (x+2) • 2 </em></h3><h3><em>   ——————————————————  =   ————————— </em></h3><h3><em>         L.C.M                 4     </em></h3><h3 /><h3><em>   R. Mult. •  R. Num.                                   ( x-24) </em></h3><h3><em>   ——————————————————  =   —————— </em></h3><h3><em>                       L.C.M                                            4   </em></h3><h3 /><h3><em>Adding up the two equivalent fractions </em></h3><h3 /><h3><em> (x+2) • 2 - ((x-24))                                           x + 28 </em></h3><h3><em> ————————————————————  =  —————— </em></h3><h3><em>          4                                                                  4   </em></h3><h3><em> </em></h3><h3><em>      x + 28 </em></h3><h3><em>  ——————  = 0  </em></h3><h3><em>      4   </em></h3><h3 /><h3 /><h3><em>When a fraction equals zero ... </em></h3><h3><em>Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero. </em></h3><h3 /><h3><em>Now, to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator. </em></h3><h3 /><h3><em>Here's how: </em></h3><h3 /><h3><em>   x+28 </em></h3><h3><em>  ———— • 4 = 0 • 4 </em></h3><h3><em>    4   </em></h3><h3><em>Now, on the left hand side, the  4  cancels out the denominator, while, on the right hand side, zero times anything is still zero. </em></h3><h3 /><h3><em>The equation now takes the shape : </em></h3><h3><em>   x+28  = 0</em></h3><h3 /><h3><em>Solve  :  x+28 = 0  </em></h3><h3 /><h3><em> Subtract  28  from both sides of the equation :  </em></h3><h3><em>                      x = -28</em></h3><h3 /><h3 /><h3 /><h3 /><h3>I hope it is helpful?</h3>
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Pls help me on this math question.I am really confused
Natali5045456 [20]

Answer:

640 m

Step-by-step explanation:

We can consider 4 seconds to be 1 time unit. Then 8 more seconds is 2 more time units, for a total of 3 time units.

The distance is proportional to the square of the number of time units. After 1 time unit, the distance is 1² × 80 m. Then after 3 time units, the distance will be 3² × 80 m = 720 m.

In the additional 2 time units (8 seconds), the ball dropped an additional

... (720 -80) m = 640 m

_____

<em>Alternate solution</em>

You can write the equation for the proportionality and find the constant that goes into it. If we use seconds (not 4-second intervals) as the time unit, then we can say ...

... d = kt²

Filling in the information related to the first 4 seconds, we have ...

... 80 = k(4)²

... 80/16 = k = 5

Then the distance equation becomes ...

... d = 5t²

After 12 seconds (the first 4 plus the next 8), the distance will be ...

... d = 5×12² = 5×144 = 720 . . . meters

That is, the ball dropped an additional 720 -80 = 640 meters in the 12 -4 = 8 seconds after the first data point.

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3 years ago
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strojnjashka [21]

Hello from MrBillDoesMath!

Answer:

Limit does not exist.

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The function 1/x has a vertical asymptote as x approaches 0 so

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