If we are talking about whole numbers, the only number in between 1 and 3 is 2 but if we are talking about numbers in general, there are an infinite amount of numbers (for example, 1.1, 1.12, 1.004, and 1.80543285 are all in between 1 and 3).
Answer:
You have a triangle and a Square!
Step-by-step explanation:
Blue = Square
Red = triangle
Here is how you find the answer.
Do remember that the term Bisect means to cut it in half.
So here it goes.
<span>5x = 3x + 10
5x - 3x = 10
2x = 10
x = 5
Then, substitute the values, so 5*5 or 3*5+10
Then, the answer for each smaller angle is 25.
</span>Remember bisect? so 25 x 2 so the final answer is 50.
Hope this is the answer that you are looking for. Thanks for posting your question!
Answer:
Step-by-step explanation:
Given the expression cosec (x) = 4 and tan(x)< 0
since cosec x = 1/sinx
1/sinx = 4
sinx = 1/4
From SOH, CAH TOA
sinθ = opposite/hypotenuse
from sinx = 1/4
opposite = 1 and hypotenuse = 4
to get the adjacent, we will use the Pythagoras theorem
adj² = 4²-1²
adj² = 16-1
adj ²= 15
adj = √15
cosx = adj/hyp = √15/4
tanx = opposite/adjacent = 1/√15
since tan < 0, then tanx = -1/√15
From double angle formula;
sin2x = 2sinxcosx
sin2x = 2(1/4)(√15/4)
sin2x = 2√15/16
sin2x = √15/8
for cos2x;
cos2x = 1-2sin²x
cos2x = 1-2(1/4)²
cos2x = 1-2(1/16)
cos2x= 1-1/8
cos2x = 7/8
for tan2x;
tan2x = tanx + tanx/1-tan²x
tan2x = 2tanx/1-tan²x
tan2x = 2(-1/√15)/1-(-1/√15)²
tan2x = (-2/√15)/(1-1/15)
tan2x = (-2/√15)/(14/15)
tan2x = -2/√15 * 15/14
tan2x = -30/14√15
tan2x = -30/7√15
rationalize
tan2x = -30/7√15 * √15/√15
tan2x = -30√15/7*15
tan2x = -2√15/7
Use the Quadratic formula,
x= -b +/- sqrt(b^2-4ac)
-------------------------
2a
x= 4 +/- sqrt(16+12)
----------------------
-6
x = 4+/- sqrt(28)
---------------
-6
x = 4 +/- 2*sqrt(7)
------------------
-6
x= 2(2+/- sqrt(7))
------------------
2(-3)
x= 2+/- sqrt(7)
--------------
-3
