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Aleks04 [339]
3 years ago
11

Isaac wants the equation below to have no solution when the missing number is placed in the box.

Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer: 4

Step-by-step explanation: To have an equation with no solution you have to get something like 0=1 meaning you have to remove all the variables. In this equation you would distribute to get xy+2y+2x=2x+12+4x where y is the missing number. then combining like terms you get xy+2x+2y=6x+12. Subtracting 2x from both sides you get xy+2y=4x+12. Now to get the variables gone y has to be 4 so that the variables to cancel out. By plugging in 4 you can see this works; 4x+8=4x+12 and by subtracting 4x from both sides you get 8=12 which is not true meaning there is no solution.

lyudmila [28]3 years ago
8 0

ANSWER

^{\boxed {}} = 4.

EXPLANATION.

The given equation is

\boxed {}(x + 2) + 2x = 2(x + 6) + 4x

Let us expand the right hand side to obtain:

\boxed {}(x + 2) + 2x = 2x + 12+ 4x

We group similar terms and keep the expression with the box on the left.

\boxed {}(x + 2)  = 2x  - 2x+ 12+ 4x

Simplify

\boxed {}(x + 2)  =  4x + 12

We can see that the value of box the will be the equation to have no solution is 4.

Let us substitute 4 for box.

4(x + 2)  =  4x + 12

4x + 8 =  4x + 12

4x - 4x = 12 - 8

0 = 4

This is not true. Hence the equation has no solution when

\boxed {} = 4

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