Question

Which function has a greater rate of change over the interval [0,2]

Answer 1

Answer:

g(x) has a greater average rate of change

Step-by-step explanation:

From the given information, the table is:

x     |    g(x)

-1          7

0           5

1            7

2            13

From this table, we have g(0)=5 and g(2)=13

The average rate of change over [a,b] of g(x) is given by: $\frac{g(b)-g(a)}{b-a}$

This implies that on the [0,2]. the average rate of change is:

$\frac{g(2)-g(0)}{2-0}=\frac{13-5}{2}=\frac{7}{2}=3.5$

Also, we have that: f(0)=-4 and f(2)=-1.

This means that the average rate of change of f(x) on [0,2] is

$\frac{f(2)-f(0)}{2-0}=\frac{-1--4}{2} =\frac{3}{2} =1.5$

Hence g(x) has a greater average rate of change on [0,2]