Which statements are true the ordered pair (1, 2) and the system of equations? y=−2x+47x−2y=3 Select each correct answer.

Mathematics

1 answer:

netineya [11]2 years ago

4 0

Ccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc

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Timothy gets a phone call from some of his friends. They say they will be at the library which is 5/8 mi away. He walks at a ste

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I think the is answer 5/4

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2 years ago

Solve the simultaneous equation y = x^2 and y = 3x - 2

gayaneshka [121]

Answer:

${x}^{2} = 3x - 2 \\ {x}^{2} - 3x + 2 = 0 \\ (x - 1)(x - 2) = 0 \\ x = 1 \: or \: x = 2 \\ for \: x \: = 1 \\ \: y = {(1)}^{2} = 1 \\ for \: x = 2 \\ y = {(2)}^{2} = 4$

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Prove the following identity : Sin α . Cos α . Tan α = (1 – Cos α) (1 + Cos α)

Umnica [9.8K]

Let's work on the left side first. And remember that
the tangent is the same as sin/cos.

sin(a) cos(a) tan(a)

Substitute for the tangent:

[ sin(a) cos(a) ] [ sin(a)/cos(a) ]

Cancel the cos(a) from the top and bottom, and you're left with

[ sin(a) ] . . . . . [ sin(a) ] which is [ sin²(a) ] That's the left side.

Now, work on the right side:

[ 1 - cos(a) ] [ 1 + cos(a) ]

Multiply that all out, using FOIL:

[ 1 + cos(a) - cos(a) - cos²(a) ]

= [ 1 - cos²(a) ] That's the right side.

Do you remember that for any angle, sin²(b) + cos²(b) = 1 ?
Subtract cos²(b) from each side, and you have sin²(b) = 1 - cos²(b) for any angle.

So, on the right side, you could write [ sin²(a) ] .

Now look back about 9 lines, and compare that to the result we got for the left side .

They look quite similar. In fact, they're identical. And so the identity is proven.

Whew !

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2 years ago

Read 2 more answers

PLEASE HELP QUICK!!!! WILL GIVE BRAINIEST!!!!!

Kipish [7]

Answer:

From top to bottom:

Slope intercept Equation: $y = \frac{3}{4} x+2$ $y=3x-2$