Solution to the linear inequality below X-4y<-12
1 answer:
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Answer:
(- 7, - 4 )
Step-by-step explanation:
Given a quadratic in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the turning point is
x = -
y = x² + 14x + 45 ← is in standard form
with a = 1, b = 14 , then
x = - = - 7
Substitute x = - 7 into the equation and evaluate for y
y = (- 7)² + 14(- 7) + 45 = 49 - 98 + 45 = - 4
coordinates of turning point = (- 7, - 4 )