(a^2-b^2)^2
(36-25)^2
11^2
121
Answer:
A =24.7° ; B = 40.6° ; C =114.7°
Step-by-step explanation:
Cosine Law
a² = b²+c²-2bc cos A
b² = c²+a² -2ca cos B
Sum of three angles of a triangle is 180°.
a = 34 ; b= 53; c = 74
Substituting the given values in the cosine law, we have
34² = 53² + 74² - 2*53 *74 * cos A
7844 cos A = 2809 + 5476 - 1156 = 7129
cos A = 7129/7844 = 0.9088
A = cos⁻¹ (0.9088) = 24.6600° = 24.7°
53² = 74² + 34² - 2 (74)(34) cos B
5032 cos B = 5476 + 1156 - 2809 = 3823
cos B = 3823/5032 = 0.7597
B = cos⁻¹ (0.7597) = 40.5622° = 40.6°
Also, A + B + C = 180°
24.7 + 40.6 + C =180
C =180 - 65.3 = 114.7°
∴ A =24.7° ; B = 40.6° ; C =114.7°
Answer:
x=-8
Step-by-step explanation:
on squaring both sides
either x-2=0 or x+8=0
either x=2 or x=-8
Putting x=2 in original equation, we get
7=7 hence, it is not an extraneous solution
Putting x=-8 in original equation
i.e. 3=-3
Hence, x=-8 is an extraneous solution (since it doesn't satisfy the original equation)
Answer: 166 students
Explanation: First your equation will be S times 15 equals 2,500 which will read as: S * 15 = 2,500 , then you will divide 2,500 by 15 which will give you 166.666667, since there cannot be .66 repeating students you will round down and the answer will be 166 students.
Answer:
11
Step-by-step explanation:
sorry if I got it wrong but from what I understand it is 11
