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3 years ago

5

Write the first four terms of the sequence whose general term is given below.

1 answer:

BaLLatris [955]3 years ago

4 0

$a_n=5(n+1)!$

Assume n starts at the value, 1.

$a_1=5(1+1)!$
$a_1=5(2)!$
$a_1=10!$

$a_2=5(2+1)!$
$a_2=5(3)!$
$a_2=15!$

$a_3=5(3+1)!$
$a_3=5(4)!$
$a_3=20!$

$a_4=5(4+1)!$
$a_4=5(5)!$
$a_4=25!$

$[a_n] = [10!~, 15!~, 20!~, 25!]$

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Anyone wanna attempt to help me

ArbitrLikvidat [17]

Answer:

t=57, u=31, v=92

Step-by-step explanation:

So we know that 180= 5x+2+2x+9+8x+4 which simplifies to 180 = 15x+15. Subtract 15 from both sides to get 165=15x and then divide by 15 to get 11=x. NOw we can plug this into the three angles as x so t = 5*11+2, t=55+2, t=57, then u = 2*11+9, u=22+9, u=31, and lastly v=8*11+4, v= 88+4, and v=92

7 0

3 years ago

What is the distance from point (– 1, 3) to the line 3x – 4y = 10?

natta225 [31]

Answer:

5 units

Step-by-step explanation:

The distance from a point (m, n ) to the line Ax + By + C = 0 is given by

d = $\frac{|Am+Bn+C|}{\sqrt{A^2+B^2} }$

For the point (- 1, 3 ) , with m = - 1 and n = 3

3x - 4y = 10 ( subtract 10 from both sides )

3x - 4y - 10 = 0

with A = 3 , B = - 4 , C = - 10

d = $\frac{|3(-1)+(-4)3-10|}{\sqrt{3^2+(-4)^2} }$

= $\frac{|-3-12-10|}{9+16}$

= $\frac{|-25|}{\sqrt{25} }$

= $\frac{25}{5}$

= 5

5 0

2 years ago

Please help ASAP what’s the abs for alll 3 of them

ad-work [718]

Don’t open the file it takes your information

6 0

3 years ago

The position d of bicyclist (measured in kilometres) is a linear function of time t (measured in minutes). At time t= 5 minutes,

satela [25.4K]

Answer:

<h2> 21 km </h2>

Step-by-step explanation:

If the bicyclist travels 7 km for every 5 minutes then it is directly proportional

5 min 7 km

15 min x

$x=\dfrac{15\cdot7}{5}=3\cdot7=21\,km$

3 0

3 years ago

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ludmilkaskok [199]

The answer would be 24 glasses because you do 8 x 3 and you get 24

3 0

3 years ago

Read 2 more answers