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son4ous [18]
4 years ago
5

Which value of the variable is a solution of the inequality?

Mathematics
1 answer:
Kitty [74]4 years ago
5 0
The value that the variable can be to be a solution to the inequality is if the variable represents -6, values of -9 and -8 are smaller than -7 as they appear even further away from zero.
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Find the slope and the
IgorC [24]

Answer:

the slope is 4 and the y-intercept is -5

Step-by-step explanation:

slope s what ever is next to the x

y-intercept is like the "normal" number.

8 0
3 years ago
Please give me the answer and explain
Ahat [919]

Answer:

Brownie is 80 times thicker than cookie.

Step-by-step explanation:

Thickness of brownie is 4 x 10∧-2 feet

Thickness of cookies is 5 x 10∧ -4 feet

Ratio = (4 x 10∧-2)/(5 x 10∧ -4) =80

Brownie is 80 times thicker than cookie.

5 0
3 years ago
Which table of values can be represented by the function y=x+4 ?
ozzi

Answer:

See explanation

Step-by-step explanation:

The given function is y=x+4

To create a table we choose some values of x and plug it into the function and solve for y.

When x=-1, y=-1+4=3

When x=0 y=0+4

When x=1, y=4+1=5

When x=2, y=6

The table looks like;

x     y

-1      3

0       4

1        5

2         6

4 0
3 years ago
figure PQRS is a parallelogram. What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S =
viktelen [127]
I believe it is C (p=140 s=40)
4 0
3 years ago
Read 2 more answers
1. Storing milk at temperatures colder than 35°F can affect its quality of taste. However, storing milk at temperatures warmer t
Zinaida [17]

1.

Storing milk at temperatures smaller than 35°F can affect its quality of taste.

hence  t > 35°F

storing milk at temperatures greater than 40°F is an unsafe food practice. hence

t < 40°F

so correct choice is

C. t > 35 AND t < 40


2.

15| x-7|+4=10|x-7|+4

subtracting 4 both side

15| x-7|+4- 4 =10|x-7|+4 - 4

15| x-7| = 10|x-7|

this is possible when |x-7| = 0

hence x - 7 = 0

x = 7

hence correct choice is

C. only x=7


3.

|x+1|+5=2

we know that , |x+1| ≥ 0

adding 5 both side

|x+1| + 5 ≥ 0 + 5

|x+1| + 5 ≥ 5

hence the relation |x+1|+5=2  is false.

C. no solution


|4x+12|=0

4x+12 = 0

x = -12/4

x = - 3

hence B. solution


|3x|=9

3x = \pm9

x =  \pm9/3

x =  \pm3

hence  

A. two solutions


8 0
3 years ago
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