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3 years ago

10 bags of chips and 8 soda cans cost $15

1 answer:

6 0

If you don’t mind me asking what is the question I’m confused because I might be able to help but I have no clue what the question is.

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Can someone help me pleaseee?

Soloha48 [4]

(2,4) cause where the lines meet

4 0

3 years ago

Read 2 more answers

Pls help!! i don’t get it at all

tigry1 [53]

Basically put it in a calculator

5 0

3 years ago

Read 2 more answers

Indicate in standard form the equation of the line passing through the given points, writing the answer in the equation

Kryger [21]

Answer:

$y + x - 6 = 0$

Step-by-step explanation:

Given

$M(0,6) \ and \ N(6,0)$

Required

Find the equation of the line

First, the slope of the line has to be calculated using the following formula;

$m = \frac{y_2 - y_1}{x_2 - x_1}$

$where\ (x_1,y_1) = (0,6) \ and \ (x_2,y_2) = (6,0)$

So, the equation becomes

$m = \frac{0 - 6}{6 - 0}$

$m = \frac{-6}{6}$

$m = -1$

The equation of the line can then be calculated using

$m = \frac{y - y_1}{x - x_1} \ or \ m = \frac{y - y_2}{x - x_2}$

$Using \ m = \frac{y - y_1}{x - x_1}$

$-1 = \frac{y - 6}{x -0}$

$-1 = \frac{y - 6}{x}$

Multiply both sides by x

$-1 * x = \frac{y - 6}{x} * x$

$-x = y - 6$

Add x to both sides

$x -x = y - 6 + x$

$0 = y - 6 + x$

Reorder

$y + x- 6 = 0$

$Using \ m = \frac{y - y_2}{x - x_2}$

$-1 = \frac{y - 0}{x - 6}$

$-1 = \frac{y}{x - 6}$

Multiply both sides by x - 6

$-1 * (x-6) = \frac{y}{x - 6} * (x-6)$

$-1 * (x-6) = y$

$-x+6 = y$

Add x - 6 to both sided

$x - 6 -x+6 = y +x - 6$

$0 = y + x - 6$

$y + x - 6 = 0$

Hence, the equation of the line is $y + x - 6 = 0$

3 0

3 years ago

The probability that a student has a Visa card (event V) is .73. The probability that a student has a MasterCard (event M) is .1

snow_lady [41]

We assumed in this answer that the question b is, Are the events V and M independent?

Answer:

(a). The probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ . (b). The events V and M are not independent.

Step-by-step explanation:

The key factor to solve these questions is to know that:

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

We already know from the question the following probabilities:

$\\ P(V) = 0.73$

$\\ P(M) = 0.18$

The probability that a student has both cards is 0.03. It means that the events V AND M occur at the same time. So

$\\ P(V \cap M) = 0.03$

The probability that a student has either a Visa card or a MasterCard

We can interpret this probability as $\\ P(V \cup M)$ or the sum of both events; that is, the probability that one event occurs OR the other.

Thus, having all this information, we can conclude that

$\\ P(V \cup M) = P(V) + P(M) - P(V \cap M)$

$\\ P(V \cup M) = 0.73 + 0.18 - 0.03$

$\\ P(V \cup M) = 0.88$

Then, the probability that a student has either a Visa card or a MasterCard is $\\ P(V \cup M) = 0.88$ .

Are the events V and M independent?

A way to solve this question is by using the concept of conditional probabilities.

In Probability, two events are independent when we conclude that

$\\ P(A|B) = P(A)$ [1]

The general formula for a conditional probability or the probability that event A given (or assuming) the event B is as follows:

$\\ P(A|B) = \frac{P(A \cap B)}{P(B)}$

If we use the previous formula to find conditional probabilities of event M given event V or vice-versa, we can conclude that

$\\ P(M|V) = \frac{P(M \cap V)}{P(V)}$

$\\ P(M|V) = \frac{0.03}{0.73}$

$\\ P(M|V) \approx 0.041$

If M were independent from V (according to [1]), we have

$\\ P(M|V) = P(M) = 0.18$

Which is different from we obtained previously;

That is,

$\\ P(M|V) \approx 0.041$

So, the events V and M are not independent.

We can conclude the same if we calculate the probability

$\\ P(V|M)$ , as follows:

$\\ P(V|M) = \frac{P(V \cap M)}{P(M)}$

$\\ P(V|M) = \frac{0.03}{0.18}$

$\\ P(V|M) = 0.1666.....\approx 0.17$

Which is different from

$\\ P(V|M) = P(V) = 0.73$

In the case that both events were independent.

Notice that

$\\ P(V|M)*P(M) = P(M|V)*P(V) = P(V \cap M) = P(M \cap V)$

$\\ \frac{0.03}{0.18}*0.18 = \frac{0.03}{0.73}*0.73 = 0.03 = 0.03$

$\\ 0.03 = 0.03 = 0.03 = 0.03$

3 0

4 years ago

Find the markup on a pair of jeans if the cost is $15.40, and the markup is 60% of the selling price.

Troyanec [42]

The markup price is $9.24. - $15.40 x 60% = $9.24

6 0

3 years ago