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3 years ago

10 bags of chips and 8 soda cans cost $15

1 answer:

6 0

If you don’t mind me asking what is the question I’m confused because I might be able to help but I have no clue what the question is.

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A bookstore is having a sale in which customers can purchase 6 books for a price of b dollars. Which expression represents the p

Evgen [1.6K]

That would be 6/b <====

5 0

3 years ago

Using a white-board with graph paper or graphing technology such as Geogebra be able to perform a reflection for a pre-image ove

Marta_Voda [28]

Explanation:

The line of reflection is the perpendicular bisector of the segment joining a point with its reflected image.

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The segment joining a point with its reflection is as short as possible consistent with the requirement that the reflected point be the same distance from the line that the original is. That means it is perpendicular to the line of reflection. Since the distance from that line is the same on either side, the line of reflection bisects the joining segment.

7 0

3 years ago

Find the value of x. A B 8 X 4 3 D x = [?] C

sergiy2304 [10]

Answer:

Step-by-step explanation:

4 x 3 = 12

8 x 3 = 24

12 / 4 = 3

24 / 4 = 6

x must be 6

5 0

2 years ago

The line through the points (1/2, 2) and (- 3/2, 4)

Amanda [17]

Answer:

y=-x+2.5

Step-by-step explanation:

8 0

3 years ago

Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f

nata0808 [166]

Via Lagrange multipliers:

$L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)$
$L_x=2xy+1+\lambda y=0$
$L_y=x^2+1+\lambda x=0$
$L_\lambda=xy-5=0$

$\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y$
$xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x$

$\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}$
$xy=5\implies y=\pm\sqrt{30}$

At these points, we get local minima of $f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}$ .

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Another way to do this is to make $f(x,y)$ a function independent of $y$ , which is made possible by the constraint.

$xy=5\implies y=\dfrac5x$
$\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x$
$\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}$

and so on.

8 0

3 years ago